MySQL 5.5-每天计算未清项目 [英] MySQL 5.5 - count open items per day

问题描述

我有一张下表只是一个快照，我要做的就是计算每个日期未清项目的数量.

I have the below table that is just a snapshot and all I want to do is to calculate the number of open items per date.

我曾经在Excel中使用简单的公式=COUNTIFS($A$2:$A$30000,"<="&E2,$B$2:$B$30000,">="&E2)来做到这一点，其中A列是Open_Date日期，B列是Close_Date日期.我想使用SQL来获得相同的结果.

I used to do it in excel with simple formula =COUNTIFS($A$2:$A$30000,"<="&E2,$B$2:$B$30000,">="&E2) where column A was the Open_Date dates and column B the Close_Date dates. I want to use SQL to get the same results.

这是我的excel快照.上面的公式.

This is my excel snapshot. Formula above.

在mysql中，我已使用T1表将其复制:

In mysql I have replicated it with T1 table:

CREATE TABLE T1
(

ID int (10),
Open_Date date,
Close_Date date);


insert into T1 values (1, '2018-12-17', '2018-12-18');
insert into T1 values (2, '2018-12-18', '2018-12-18');
insert into T1 values (3, '2018-12-18', '2018-12-18');
insert into T1 values (4, '2018-12-19', '2018-12-20');
insert into T1 values (5, '2018-12-19', '2018-12-21');
insert into T1 values (6, '2018-12-20', '2018-12-22');
insert into T1 values (7, '2018-12-20', '2018-12-22');
insert into T1 values (8, '2018-12-21', '2018-12-25');
insert into T1 values (9, '2018-12-22', '2018-12-26');
insert into T1 values (10, '2018-12-23', '2018-12-27');

第一步是创建带有日期的表，以防Date_open中有任何间隙.因此，目前我的代码是

First step was to create the table with dates in case there any gap in Date_open. So my code at the moment is

SELECT
    d.dt, Temp_T1.*
FROM
(
    SELECT '2018-12-17' AS dt UNION ALL
    SELECT '2018-12-18' UNION ALL
    SELECT '2018-12-19' UNION ALL
    SELECT '2018-12-20' UNION ALL
    SELECT '2018-12-21' UNION ALL
    SELECT '2018-12-22' UNION ALL
    SELECT '2018-12-23' UNION ALL
    SELECT '2018-12-24'
) d

LEFT JOIN 
(SELECT * FROM T1) AS Temp_T1
ON Temp_T1.Open_Date = d.dt

我不知道如何计算与excel中相同的值?

I am lost how to calculate the same values as I do in excel?

推荐答案

您想使用GROUP BY为d派生表中的每个日期添加一行.

You want to use GROUP BY to make one row for each date in your d derived table.

然后将d连接到t1表，其中d.dt在打开和关闭日期之间.

Then join d to the t1 table where the d.dt is between the open and close dates.

SELECT
    d.dt, COUNT(*) AS open_items
FROM
(
    SELECT '2018-12-17' AS dt UNION ALL
    SELECT '2018-12-18' UNION ALL
    SELECT '2018-12-19' UNION ALL
    SELECT '2018-12-20' UNION ALL
    SELECT '2018-12-21' UNION ALL
    SELECT '2018-12-22' UNION ALL
    SELECT '2018-12-23' UNION ALL
    SELECT '2018-12-24'
) d
LEFT JOIN T1 ON d.dt BETWEEN t1.Open_Date and t1.Close_Date
GROUP BY d.dt;

输出:

+------------+------------+
| dt         | open_items |
+------------+------------+
| 2018-12-17 |          1 |
| 2018-12-18 |          3 |
| 2018-12-19 |          2 |
| 2018-12-20 |          4 |
| 2018-12-21 |          4 |
| 2018-12-22 |          4 |
| 2018-12-23 |          3 |
| 2018-12-24 |          3 |
+------------+------------+

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