如何从子查询中的不同表中获取特定行数 [英] How to get number of specific rows from a different table in a subquery
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问题描述
我知道有可能,但是我没有足够的经验来知道如何执行子查询.
情况如下:
I know it's possible, but I'm not experienced enough to know how to do subqueries.
Here's the situation:
Table 1:
+--------------------+--------------------+
| v_id | v_name |
+--------------------+--------------------+
| 1 | v_name1 |
+--------------------+--------------------+
| etc...
Table 2:
+--------------------+--------------------+
| a_id | a_name |
+--------------------+--------------------+
| 1 | a_name1 |
+--------------------+--------------------+
| etc...
Table 3:
+--------------------+--------------------+
| v_id | a_id |
+--------------------+--------------------+
| 1 | 1 |
+--------------------+--------------------+
| 1 | 2 |
+--------------------+--------------------+
| 1 | 3 |
+--------------------+--------------------+
| 2 | 3 |
+--------------------+--------------------+
| 2 | 1 |
+--------------------+--------------------+
我认为这是一种很常见的情况.
因此,我在Table 1
和Table 2
中具有唯一的条目.
我想SELECT
从Table 1
的所有行,并获取(作为每行的最后一个单元格)具有Table 3
中的相应值的行数.
I believe this is a quite common situation.
So, I have unique entries in Table 1
and Table 2
.
I want to SELECT
all rows from Table 1
and get (as the last cell in each row) the number of rows with the corresponding value in Table 3
.
这不起作用:
SELECT t1.* , COUNT(SELECT t3.* FROM `table_3` t3 WHERE t3.v_id = t1.v_id) as entries
FROM `table 1` t1;
我敢肯定,这里的专家会告诉我,这都是错误的,但是坦率地说,这就是我想要的(还有一些有用的解决方案!). ;)
I'm sure I'm gonna be told off by experts here that it's all wrong, but frankly, that's what I'm looking for (and some helpful solution as well!). ;)
推荐答案
使用:
SELECT t1.*,
COALESCE(x.num_rows, 0) AS entries
FROM `table 1` t1
LEFT JOIN (SELECT t3.v_id,
COUNT(*) 'num_rows'
FROM `table_3` t3
GROUP BY t3.v_id) x ON x.v_id = t1.v_id
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