mysql在where子句中从同一表中选择两次具有不同日期的列 [英] mysql Select one column twice from the same table with different dates in the where clause

问题描述

我有两个SQL查询，我想将它们合并到一个SQL查询中并显示在一张表上:

I have two sql queries which i want to combine in one SQL Query and display on one table:

SELECT subname,subscribers as sub1 FROM reports_subreport where  country ='1' and mp='0' and date ='2013-10-15' and NOT(subname LIKE '%Test%')  order by site,subname


SELECT subscribers as sub2 FROM reports_subreport where country ='1' and mp='0' and date ='2013-10-08' and NOT(subname LIKE '%Test%')  order by site,subname

应该在表格中显示类似这样的内容:

Should Display something Like This in a table:

子名称 sub1 sub2

ENT 222202

ENT 222 202

因为我是mysql和php的新手，所以请您在这里帮助我吗?

Could you please help me out here because iam new to mysql and php?

推荐答案

已经给出了一些更好的专业答案，但这是最好的理解方法

There are some better and professional answers already been given, but this one is best to understand what is going around

SELECT subname, 

    (SELECT subscribers 
     FROM reports_subreport 
     WHERE country ='1' AND mp='0' 
     AND date ='2013-10-15' 
     AND NOT(subname LIKE '%Test%') 
     ORDER BY site,subname LIMIT 1) AS sub1,

    (SELECT subscribers 
     FROM reports_subreport 
     WHERE country ='1' AND mp='0' 
     AND date ='2013-10-08' 
     AND NOT(subname LIKE '%Test%') 
     ORDER BY site,subname LIMIT 1) AS sub2,

FROM reports_subreport WHERE country ='1' AND mp='0' 
AND date ='2013-10-15' AND NOT(subname LIKE '%Test%') 
ORDER BY site,subname

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