PHP多重选择表单可在MySQL中插入多行 [英] PHP multiple select form to insert multiple rows in MySQL

问题描述

我有以下代码，用于使用PHP将记录插入MySQL数据库.表单元素是多项选择，当仅选择一个选项时，它可以正常工作.当我选择多个选项时，仅插入最后一个选项.如何让表单为多项选择中选择的每个选项创建新行?

I have the following code used to insert a record using PHP into a MySQL database. The form element is a multiple select that works fine when only one option is selected. When I choose more than 1 option, only the last option is inserted. How do I have the form create a new row for each option selected in the multiple select?

if ((isset($_POST["MM_insert"])) && ($_POST["MM_insert"] == "InsertForm")) {
  $insertSQL = sprintf("INSERT INTO emplikons (EmpNo, IconId) VALUES (%s, %s)",
                       GetSQLValueString($_POST['insertRecordID'], "text"),
                       GetSQLValueString($_POST['icons'], "int"));

  mysql_select_db($database_techsterus, $techsterus);
  $Result1 = mysql_query($insertSQL, $techsterus) or die(mysql_error());

这是form元素的代码.它使用一个记录集从另一个表中动态提取值:

This is the code of the form element. It uses a recordset to dynamically pull values from another table:

<select name="icons" size="10" multiple="multiple">
            <?php
do {  
?>
            <option value="<?php echo $row_icons['id']?>"><?php echo $row_icons['name']?></option>
            <?php
} while ($row_icons = mysql_fetch_assoc($icons));
  $rows = mysql_num_rows($icons);
  if($rows > 0) {
      mysql_data_seek($icons, 0);
      $row_icons = mysql_fetch_assoc($icons);
  }
?>
          </select>

推荐答案

在选择的名称中添加[]，以获取所有选择的值的数组.

add [] to the name of the select, to get an array of all selected values.

<select name="icons[]" size="10" multiple="multiple">

然后，从$_POST / $_GET ...(假设form method="post")中读取

Then, read from $_POST / $_GET... (assuming form method="post")

$sql = '';
foreach ($_POST['icons'] as $icon) {

    // no idea where to get EmpNo from, let's assume it is in $empno.
    $sql .= "('$empno','$icon'),";

}

$sql = "INSERT INTO tablename (EmpNo, IconId) VALUES " . trim($sql,',');

// Now, please use mysqli_* or PDO instead of mysql_* 

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