使用DOMDocument按类名获取所有元素 [英] Get all elements by class name using DOMDocument
本文介绍了使用DOMDocument按类名获取所有元素的处理方法，对大家解决问题具有一定的参考价值，需要的朋友们下面随着小编来一起学习吧！
问题描述
这个问题似乎已经回答了无数次，但我仍然似乎无法将所有内容放在一起.
This question seems to have been answered numerous times but i still cant seem to put the pieces together.
我想按名称获取每个类的节点值.例如
I would like to get node value of every class by name. for example
<td class="thename"><strong>32</strong></td>
<td class="thename"><strong>12</strong></td>
我想抓住32和12.我假设这需要某种for循环，但不确定如何实现它.这是我到目前为止所拥有的
i would like to grab the 32 and the 12. I assume this requires for sort of for loop but not sure exactly how to go about implementing it. Here's what i have so far
$domain = "http://domain.com";
$dom = new DOMDocument();
$dom->loadHTMLFile($domain);
$xpath = new DomXpath($dom);
$div = $xpath->query('//*[@class="thename"]')->item(0);
$stuff = $div ->textContent;
echo($stuff);
推荐答案
这是您要寻找的吗?
$result = array();
$doc = <<< HTML
<html>
<body>
<div>1
<span>2</span>
</div>
<div>3</div>
<div>4
<span class="class1"><strong>5</strong></span>
<span class="class1"><strong>6</strong></span>
<span>7</span>
</div>
</body>
</html>
HTML;
$classname = "class1";
$domdocument = new DOMDocument();
$domdocument->loadHTML($doc);
$a = new DOMXPath($domdocument);
$spans = $a->query("//*[contains(concat(' ', normalize-space(@class), ' '), ' $classname ')]");
for ($i = $spans->length - 1; $i > -1; $i--) {
$result[] = $spans->item($i)->firstChild->nodeValue;
}
echo "<pre>";
print_r($result);
exit();
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