r:3D表面图 [英] r : 3D surface plot

问题描述

假设我有一个x，y，z的数据帧，其中x任意y是坐标，z是高度.如何在x和y平面上创建z的覆盖层. 我尝试使用黄土函数创建毯子

data.loess = loess(z~x*y,data =data.df)
data.fit = expand.grid(list(x = seq(min(x),max(x),0.1), y = seq(min(y),max(y),0.1)))
z = predict(data.loess, newdata =data.fit)

但是预测的z值与原始高度不一致.

像scatterplot3d这样的函数仅给我分散的点，如何获得带有丘陵和山谷的表面?

解决方案

我不知道与原始高度不一致"是什么意思，但为什么不看:

persp(z)

x = seq(1,10,0.1); y = seq(1,10,0.1)
z= outer(x,y,"*")
data =data.frame(x=rep(x, times=91), y=rep(y, each=91), z=c(z) )
data.loess = loess(z~x*y,data =data)
data.fit = expand.grid(list(x = seq(min(x),max(x),0.1), y = seq(min(y),max(y),0.1)))
z = predict(data.loess, newdata =data.fit)
persp(z)

Assuming i have a dataframe of x , y , z wherein x any y are the coordinates and z is the height. How do I create a blanket of z over the x and y plane. I tried using the loess function to create a blanket

data.loess = loess(z~x*y,data =data.df)
data.fit = expand.grid(list(x = seq(min(x),max(x),0.1), y = seq(min(y),max(y),0.1)))
z = predict(data.loess, newdata =data.fit)

But the predicted z value is not in coherence with the original height.

Functions like scatterplot3d gives me only the scattered dots,how do I get a surface with hills and valley?

解决方案

I have no idea what the phrase "not in coherence with original height" means, but why not look at:

persp(z)

x = seq(1,10,0.1); y = seq(1,10,0.1)
z= outer(x,y,"*")
data =data.frame(x=rep(x, times=91), y=rep(y, each=91), z=c(z) )
data.loess = loess(z~x*y,data =data)
data.fit = expand.grid(list(x = seq(min(x),max(x),0.1), y = seq(min(y),max(y),0.1)))
z = predict(data.loess, newdata =data.fit)
persp(z)

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