从数组中获取两个随机的非连续且唯一的元素 [英] Getting two random non consecutive and unique elements from an array

问题描述

我正在尝试从一个不连续的列表中获取两个唯一的随机元素.数组形成如下

Hi I am trying of getting two unique random elements from a list that are not consecutive. The array is formed as following

[
  {"id": 1, "name": "Monday", "workers": []},
  {"id": 2, "name": "Tuesday", "workers": []},
  {"id": 3, "name": "Wednesday", "workers": []},
  {"id": 4, "name": "Thursday", "workers": []},
  {"id": 5, "name": "Friday", "workers": []},
]

我设法获得了两个独特的元素，如下所示:

And I managed to get two unique elements as following :

 getTwoNonConsecutiveDays = () => {
    var days = require('./weeks.json');

    let selected = [];
    let randomday = () => {
      const shuffled = days.sort(() => 0.5 - Math.random());

      // Get sub-array of first n elements after shuffled
      selected = shuffled.slice(0, 2);

但是，当我试图将条件设为不连续时，这是行不通的

However when I am trying to put condition not to be consecutive is not working

      if (selected[0].id === selected[1].id) {

     console.log('greseala')}

     selected[0].id

推荐答案

您可以这样处理:

var days = require('./weeks.json');
 function randomIndex(array){
        return Math.floor(Math.random() * array.length);
 }
 
 function randomPair(array){
        var index1 = randomIndex(array), index2;
    do{
        index2 = randomIndex(array);
    }while(Math.abs(index1 - index2) < 2);
    return [array[index1], array[index2]];
 }
console.log(randomPair(days));

注意:虽然@Yevgen Gorbunkov在评论中说，虽然循环和退出条件不适用于小型阵列.可以添加其他if条件来检查数组的长度.

Note: While loop and exit condition are inappropriate for small arrays, as @Yevgen Gorbunkov said in comment. An additional if condition can be added for checking the length of the array.

更新:在根据@Andreas注释更新条件时，请使用Math.abs而不是多次检查.

Update: While condition update based on @Andreas comment, use of Math.abs instead of multiple checks.

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