如何通过使用list_objects_v2从S3获取1000个以上的对象? [英] How to get more than 1000 objects from S3 by using list_objects_v2?

问题描述

我在s3上有超过500,000个对象.我正在尝试获取每个对象的大小.我为此使用了以下python代码

I have more than 500,000 objects on s3. I am trying get the size of each object. I am using the following python code for that

import boto3

bucket = 'bucket'
prefix = 'prefix'

contents = boto3.client('s3').list_objects_v2(Bucket=bucket,  MaxKeys=1000, Prefix=prefix)["Contents"]

for c in contents:
    print(c["Size"])

但这只是给了我前1000个对象的大小.根据文档，我们不能获得更多1000.有什么办法可以使我获得更多?

But it just gave me the size of top 1000 objects. Based on the documentation we can't get more 1000. Is there any way I can get more than that?

推荐答案

使用响应中返回的ContinuationToken作为后续调用的参数，直到响应中返回的IsTruncated值为false.

Use the ContinuationToken returned in the response as a parameter for subsequent calls, until the IsTruncated value returned in the response is false.

这可以分解为一个整洁的生成器函数:

This can be factored into a neat generator function:

def get_all_s3_objects(s3, **base_kwargs):
    continuation_token = None
    while True:
        list_kwargs = dict(MaxKeys=1000, **base_kwargs)
        if continuation_token:
            list_kwargs['ContinuationToken'] = continuation_token
        response = s3.list_objects_v2(**list_kwargs)
        yield from response.get('Contents', [])
        if not response.get('IsTruncated'):  # At the end of the list?
            break
        continuation_token = response.get('NextContinuationToken')

for file in get_all_s3_objects(boto3.client('s3'), Bucket=bucket, Prefix=prefix):
    print(file['size'])

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