Android:在Toast上使用onBackPressed()的正确方法 [英] Android: Proper Way to use onBackPressed() with Toast

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问题描述

我写了一段代码,将提示用户是否要退出,请他们再按一次.目前,我的代码在一定程度上可以正常工作,但是我知道代码编写得很差,并且我认为有更好的方法可以做到这一点.任何建议都会有所帮助!

I wrote a piece of code that will give the user a prompt asking them to press back again if they would like to exit. I currently have my code working to an extent but I know it is written poorly and I assume there is a better way to do it. Any suggestions would be helpful!

代码:

public void onBackPressed(){
    backpress = (backpress + 1);
    Toast.makeText(getApplicationContext(), " Press Back again to Exit ", Toast.LENGTH_SHORT).show();

    if (backpress>1) {
        this.finish();
    }
}

推荐答案

我将实现一个对话框,询问用户是否要退出,然后调用super.onBackPressed().

I would implement a dialog asking the user if they wanted to exit and then call super.onBackPressed() if they did.

@Override
public void onBackPressed() {
    new AlertDialog.Builder(this)
        .setTitle("Really Exit?")
        .setMessage("Are you sure you want to exit?")
        .setNegativeButton(android.R.string.no, null)
        .setPositiveButton(android.R.string.yes, new OnClickListener() {

            public void onClick(DialogInterface arg0, int arg1) {
                WelcomeActivity.super.onBackPressed();
            }
        }).create().show();
}

在上面的示例中,您需要用活动名称替换WelcomeActivity.

In the above example, you'll need to replace WelcomeActivity with the name of your activity.

这篇关于Android:在Toast上使用onBackPressed()的正确方法的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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