alertdialog-必须调用removeView [英] alertdialog - removeView has to get called

问题描述

我有一个带有editText区域的警报对话框.当我第二次调用它时，该应用程序崩溃并显示错误:

I have a alert dialog with a editText area. When I call it a second time, the app crashes with error:

02-28 23:25:08.958: E/AndroidRuntime(11533): java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

这是我的代码:

alert = new AlertDialog.Builder(this);

    String txt_title = context.getResources().getString(R.string.txt_head_search_coord);
    String txt_message = context.getResources().getString(R.string.txt_mess_search_coord);
    alert.setTitle(txt_title);
    alert.setMessage(txt_message);

    // Set an EditText view to get user input 
    final EditText input = new EditText(this);
    alert.setView(input);

    alert.setPositiveButton(context.getResources().getString(R.string.Accept), new DialogInterface.OnClickListener() {
    public void onClick(DialogInterface dialog, int whichButton) {
            String value = input.getText().toString();

            // Do something with value!

            dialog.dismiss();
        }
    });

    alert.setNegativeButton(context.getResources().getString(R.string.Cancel), new DialogInterface.OnClickListener() {
        public void onClick(DialogInterface dialog, int whichButton) {
            dialog.dismiss();
        }
    });

    //UTM Koordinate suchen
    btn_search_coord.setOnClickListener(new OnClickListener()
    {
        public void onClick(View v)
        {
            alert.show();
        }
    });

警报是全局定义的，因此我可以在onClickListener中调用

the alert is defined globally so I can call it in the onClickListener

我已经关闭了我的对话框...

I'm already dismissing my dialog...

推荐答案

AlertDialog.Builder.show从Builder的内容(包括在setView.

因此，您的input将同时添加到alerts中.为防止这种情况，请使用create创建AlertDialog的最终实例，并在该实例上调用show:

Therefore, your input will be added to both the alerts. To prevent this, use create to create a final instance of your AlertDialog and call show on this one:

final AlertDialog alertDialog = alert.create();

[...]
// in onClick
alertDialog.show();

从更广泛的角度来看，应该使用showDialog(int id)以及关联的方法onCreateDialog和onPrepareDialog.但是，如果您使用Fragments，则现在不建议使用所有这些，在这种情况下，您应该使用DialogFragment

On a broader perspective, you should use showDialog(int id) and the associated methods onCreateDialog and onPrepareDialog. However, all this is now deprecated if you use Fragments, in which case you should use a DialogFragment

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