如何检测Android应用程序是否正在使用Espresso运行UI测试 [英] How to detect whether android app is running UI test with Espresso

问题描述

我正在为Android编写一些Espresso测试.我正在运行以下问题:

I am writing some Espresso tests for Android. I am running in the the following problem:

为了使某些测试用例正常运行，我需要禁用应用程序中的某些功能.因此，在我的应用中，我需要检测我是否正在运行Espresso测试，以便可以将其禁用.但是，我不想使用BuildConfig.DEBUG，因为我不想在调试版本中禁用这些功能.另外，我想避免创建新的buildConfig，以免创建太多的构建变体(我们已经定义了很多样式).

In order for a certain test case to run properly, I need to disable some features in the app. Therefore, in my app, I need to detect whether I am running Espresso test so that I can disable it. However, I don't want to use BuildConfig.DEBUG to because I don't want those features to be disabled in a debug build. Also, I would like to avoid creating a new buildConfig to avoid too many build variants to be created (we already have a lot of flavors defined).

我一直在寻找一种定义buildConfigField进行测试的方法，但是我在Google上找不到任何引用.

I was looking for a way to define buildConfigField for test but I couldn't find any reference on Google.

推荐答案

与CommonsWare的答案结合在一起.这是我的解决方案:

Combined with CommonsWare's answer. Here is my solution:

我定义了一个AtomicBoolean变量和一个函数来检查它是否正在运行测试:

I defined an AtomicBoolean variable and a function to check whether it's running test:

private AtomicBoolean isRunningTest;

public synchronized boolean isRunningTest () {
    if (null == isRunningTest) {
        boolean istest;

        try {
            Class.forName ("myApp.package.name.test.class.name");
            istest = true;
        } catch (ClassNotFoundException e) {
            istest = false;
        }

        isRunningTest = new AtomicBoolean (istest);
    }

    return isRunningTest.get ();
}

这避免了每次需要检查值时都进行try-catch检查，并且仅在第一次调用此函数时运行检查.

This avoids doing the try-catch check every time you need to check the value and it only runs the check the first time you call this function.

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