结果从广播接收器返回 [英] Result Back from Broadcast Receiver

问题描述

我正在从应用程序A向应用程序B发送广泛广播，应用程序B具有BroadCastReceiver来处理意图.

I am sending a broadCast from App A to app B, app B has a BroadCastReceiver to handle intent.

现在，我在App B的BroadcastReceiver的onReceive中进行了一些操作，然后我想将结果返回给App A，这样我就可以进行回调，并在结果为正数时继续操作.

Now I do some operation in onReceive in App B's BroadcastReceiver and then I want to get result back to App A, so that I can have a callback, and continue operations if result is positive.

在一些代码下面.

在应用B内部:

public class TripBackupReceiver extends BroadcastReceiver {
@Override
    public void onReceive(Context arg0, Intent arg1) {
        System.out.println("broadcast Received");

        // send result back to Caller Activity
    }
}  

内部应用A:

Intent intent = new Intent("a_specified_action_string");
sendBroadcast(intent);  

有人可以解决这个问题吗，请向我提出一些建议.谢谢！

Can anybody have any solution for this problem, please guide me with some suggestions. Thanks!!

推荐答案

我正在寻找类似的东西. 这极大地帮助了我.

I was looking for something similar. This helped me tremendously.

基本上，代替使用sendBroadcast(Intent)，请尝试使用合适的sendOrderedBroadcast()形式，该形式允许设置BroadcastReceiver来处理Receiver的结果.一个简单的例子:

Basically, instead of a sendBroadcast(Intent) try using a suitable form of sendOrderedBroadcast() which allows setting a BroadcastReceiver to handle results form a Receiver. A simple example:

sendOrderedBroadcast(intent, null, new BroadcastReceiver() {
        @SuppressLint("NewApi")
        @Override
        public void onReceive(Context context, Intent intent) {
            Bundle results = getResultExtras(true);

            String trail = results.getString("breadcrumb");
            results.putString("breadcrumb", trail + "->" + "sometext");
            Log.i(TAG, "Final Result Receiver = " + results.getString("breadcrumb", "nil"));
        }
    }, null, Activity.RESULT_OK, null, null);  

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