如何使用意图选择xml文件并动态解析 [英] how to use intent to pick a xml file and parse it dynamically

问题描述

我想使用Intent在我的应用程序内选择一个xml文件，然后动态解析它.我知道解析和显示过程，但是我的主要问题是输入流.请注意，xml的选择应动态进行，而不要在资产中进行.有人可以帮助我吗?

I wanted to use intent to pick a xml file inside of my app and then parse it dynamically. I know the parsing and showing process but my main problem is with the inputstream . Please notice that picking xml should be done dynamically not in assets . can anyone help me plz?

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    if(requestCode==PICKFIlE_RESULT_CODE) {
        if (resultCode == RESULT_OK) {
            File file = null;



            String filepath = data.getData().getPath();
            file = new File(filepath);
            String v = file.getAbsolutePath();
            try
            {

                InputStream is = new FileInputStream(v);
                DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
                DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
                Document doc = dBuilder.parse(is);
                Element element = doc.getDocumentElement();
                element.normalize();
                NodeList nList = doc.getElementsByTagName("user");

                for(int i=0;i<nList.getLength();i++)
                {
                    Node node = nList.item(i);
                    if(node.getNodeType()==Node.ELEMENT_NODE)
                    {
                        Element element2 = (Element)node;
                        textView.setText(textView.getText()+"\nName : "+getValue("name",element2)+"\n");
                        textView.setText(textView.getText()+"\nSurname : "+getValue("surname",element2)+"\n");
                        textView.setText(textView.getText()+"\nSalary : "+getValue("salary",element2)+"\n");
                    }
                }
            }
            catch (Exception e)
            {

            }



public void onClick(View v) {
final static private int PICKFILE_RESULT_CODE =10;

    try {
        Intent intent = new Intent();
        intent.setType("file/*");

        intent.putExtra(Intent.EXTRA_ALLOW_MULTIPLE,true);
        intent.setAction(Intent.ACTION_GET_CONTENT);
        startActivityForResult(intent, PICKFIlE_RESULT_CODE);

    }
    catch (Exception e)
    {
        Toast.makeText(getApplicationContext(),"No file found",Toast.LENGTH_LONG).show();
    }
}

推荐答案

首先，file/*不是有效的MIME类型.使用有效的MIME类型，如果您要接受任何内容，请使用*/*.

First, file/* is not a valid MIME type. Use a valid MIME type, or */* if you want to accept anything.

第二，ACTION_GET_CONTENT返回Uri.该Uri不是文件.摆脱所有File逻辑.使用ContentResolver(来自getContentResolver())和openInputStream()来获取InputStream，该内容由Uri标识.

Second, ACTION_GET_CONTENT returns a Uri. That Uri is not a file. Get rid of all your File logic. Use a ContentResolver (from getContentResolver()) and openInputStream() to get an InputStream on the content identified by the Uri.

这篇关于如何使用意图选择xml文件并动态解析的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！