片段内的android webview中的“后退"按钮 [英] Back button in android webview within a fragment

问题描述

我已经在一个片段中创建了一个Web视图，但是当我尝试按后退"按钮时，它杀死了该应用程序而不是返回.我想要的是当我按下后退"按钮时返回，如果我已经在主页上，则后退"按钮应该会终止该应用程序.

I have created a webview within a fragment however when I am trying to press the back button, it is killing the app instead of going back. What i want is to go back when i press the back button and if i am already on home page the back button should kill the app.

我尝试使用给定链接中的所有解决方案.

I have tried using all the solution in the given link.

如何添加返回"片段中的WebView中有功能吗?

请帮助.

推荐答案

您可以重写getActivity的onBackPressed()方法，并通过调用getFragmentManager().popBackStackImmediate()来检查后堆栈中是否有任何先前的片段要弹出. getSupportFragmentManager().popBackStackImmediate()如下代码:

You can override the Activity's onBackPressed() method and check if there is any previous fragment in the backstack to pop back by calling getFragmentManager().popBackStackImmediate() or getSupportFragmentManager().popBackStackImmediate() like the code below:

@Override
public void onBackPressed() {
    if (!getFragmentManager().popBackStackImmediate()) {
        super.onBackPressed();        
    }
}

在调用commit()将fragmenttransaction添加到backstack之前，请不要忘记调用.addToBackStack(null).

Don't forget to call .addToBackStack(null) before you call commit() to add the fragmenttransaction to the backstack.

如果您想按后退"按钮返回上一个网页，而用户在返回上一个片段之前已在WebView中导航，则可以执行以下操作:

And if you want to press back button to go back to previous webpage user has navigated in the WebView before go back to previous fragment, you can do this:

@Override
public void onBackPressed() {
    if (webView.canGoBack()) {
            webView.goBack();
    } else if (!getFragmentManager().popBackStackImmediate()) {
        super.onBackPressed();        
    }
}

并记住通过调用webView.setWebViewClient(new WebViewClient())来设置webView以加载WebView中的任何网页.

And remember to set your webView to load any webpage in the WebView by calling webView.setWebViewClient(new WebViewClient());

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