如何检测在TabLayout中每个单个选项卡上的单击? [英] How to detect a click on every single tab in tablayout?

问题描述

我有一个Viewpager，它的页面不确定，因为用户也可以添加页面.可以，但是我不知道如何使我的用户删除这些页面.我尝试使用下面的代码在每个选项卡上实现长按监听器，但是它不起作用.

I have a viewpager with undetermined pages, because the user can add pages too. Thats okay, but I have no idea how to make it possible, that my user could delete those pages. I have tried to implement a long click listener on every tab with the code below, but it is not working.

然后如何检测单击了哪个选项卡?

Then how to detect which one tab is clicked?

for (tabCounter = 0; tabCounter < DataOfPages.size(); tabCounter++) {
        tabLayout.getTabAt(tabCounter).setOnLongClickListener(new View.OnLongClickListener() {
            @Override
            public boolean onLongClick(View v) {
                dataSource.open();
                dataSource.deleteById(tabCounter);
                dataSource.close();

                setupViewPager(viewPager);
                return true;
            }
        });
    }

推荐答案

每个TAB的LongClick侦听器的实现:

Implementation of LongClick listener to each TAB:

LinearLayout tabStrip = (LinearLayout) tabLayout.getChildAt(0);

for (int i = 0; i < tabStrip.getChildCount(); i++) {

    // Set LongClick listener to each Tab        
    tabStrip.getChildAt(i).setOnLongClickListener(new View.OnLongClickListener() {
        @Override
        public boolean onLongClick(View v) {

            Toast.makeText(getApplicationContext(), "Tab clicked" , Toast.LENGTH_SHORT).show();
            return true;
        }
    });
}

希望这会有所帮助〜

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