React native-对象作为React子对象无效(找到:带有键{$$ typeof，type，key，ref，props，_owner，_store}的对象) [英] React native - objects are not valid as a React child (found: object with keys {$$typeof, type, key, ref, props, _owner, _store})

问题描述

我是React Native的新手，并且在下面引用了一个错误:

I'm new to React Native and I'm getting an error quoted below:

对象作为React子对象无效(找到:带有键{$$ typeof，类型，键，ref，props，_owner，_store}的对象).如果要渲染子级集合，请改用数组.

Objects are not valid as a React child (found: object with keys {$$typeof, type, key, ref, props, _owner, _store}). If you meant to render a collection of children, use an array instead.

除了样式:这是组件文件中包含的所有代码:

Here's my whole code included in the component file, except styling:

import React, { Component } from 'react';
import { View, Text, TextInput, TouchableOpacity, Image, StyleSheet } from 'react-native';
import firebase from 'firebase';

class LoginForm extends Component {

    state = { email: '', password: '', error: '', loading: false };

    onButtonPress(){
        const email = this.state.email;
        const password = this.state.password;

        this.setState({error: '', loading: true});

        firebase.auth().signInWithEmailAndPassword(email, password)
            .then(this.onLoginSuccess.bind(this))
            .catch(() => {
                firebase.auth().createUserWithEmailAndPassword(email, password)
                .then(this.onLoginSuccess.bind(this))
                .catch(this.onLoginFail.bind(this));
            });
    }

    onLoginSuccess(){
        this.setState({email: '', password: '', error: '', loading: false});
    }

    onLoginFail(){
        this.setState({error: 'Nie udalo sie utworzyc konta.', loading: false});
    }

    render(){
        return(
            <View style={styles.container}>
                <View style={styles.imageContainer}>
                    <Image 
                        style={styles.image}
                        source={require('../images/loginIcon.png')}
                    />
                </View>
                <View style={styles.formContainer}>
                    <TextInput
                        style={styles.input}
                        placeholder="Email..."
                        placeholderTextColor='rgba(255,255,255,0.9)'
                        underlineColorAndroid='rgba(0,0,0,0)'
                        onChangeText={(email) => this.setState({email: email})}
                        value={this.state.email}
                        autoCorrect={false}
                    />
                    <TextInput
                        style={styles.input}
                        placeholder="Hasło..."
                        placeholderTextColor='rgba(255,255,255,0.9)'
                        underlineColorAndroid='rgba(0,0,0,0)'
                        autoCorrect={false}
                        onChangeText={(password) => this.setState({password: password})}
                        value={this.state.password}
                        secureTextEntry
                    />
                    <TouchableOpacity style={styles.buttonContainer}>
                        <Text style={styles.button}>
                            Zaloguj się
                        </Text>
                    </TouchableOpacity>
                    <Text style={styles.error}>
                        {this.state.error}
                    </Text>
                </View>
            </View>
        );
    }
}

我很困惑如何解决该问题.预先感谢.

I'am quite confused how to fix that issue. Thanks in advance.

推荐答案

尝试一下:

从App.js中删除firebase导入语句:

Remove the firebase import statement from App.js:

import firebase from 'firebase'

在Firebase初始化时，创建一个常量:

On Firebase initialization create a constant:

initializeFirebase() {
  const firebase = require("firebase");

  // Initialize Firebase
  var config = {
  ...
  };
  firebase.initializeApp(config);

  //inicializando o firestore
  const firestore = require("firebase/firestore");
  db = firebase.firestore();
  db.settings({ timestampsInSnapshots: true });
}

componentWillMount() {
  this.initializeFirebase();
...
}

对我来说，这种解决方法非常有效！

To me this workaround works very well!

这篇关于React native-对象作为React子对象无效(找到:带有键{$$ typeof，type，key，ref，props，_owner，_store}的对象)的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！