Android VOIP应用程序，无法访问互联网 [英] Android VOIP application without access to internet
问题描述
我需要在2个android设备之间开发VOIP应用程序.
据我所知，有一个用于此目的的SIP协议，但是它需要重新注册到SIP服务器，并需要访问Internet才能进行SIP信令.
有没有办法在没有互联网的情况下在android中创建VOIP应用程序?
I need to develop the VOIP application between 2 android devices.
As I know there is a SIP protocol used for this purpose but it requires registation to SIP server and access to internet for SIP signaling.
Is any way to create VOIP application in android without internet access?
推荐答案
当然可以！为什么需要互联网?只要您都连接到同一网络就可以了！以下是适用的应用程序的Java和xml.
Of course it is possible! Why you would need the internet? As long as you are both connected to the same network that is fine! Below is the java and xml for a working app.
在启动时，它将为您提供您自己的本地端口，例如"52022".然后，我们输入另一部电话的IP地址和其随机生成的端口号，然后按connect.它们的作用完全相同，万事通！该测试应用程序显然需要您在附近交换端口号，但是在我正确的应用程序中，我可以轻松地在连接之前请求每个端口号.希望这会有所帮助！
On start up it will provide you with your own local port, for example "52022".. this is random every time and unfortunately that can't be helped. We then enter the IP address of the other phone and THEIR randomly generated port number and press connect. They do exactly the same and hooray you're connected! This test app obviously requires you to be close by to exchange port numbers, but in my proper app I was easily able to request each port number before connecting. Hope this helps!
public class MainActivity extends Activity {
AudioGroup m_AudioGroup;
AudioStream m_AudioStream;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder().permitAll().build();
StrictMode.setThreadPolicy(policy);
try {
AudioManager audio = (AudioManager) getSystemService(Context.AUDIO_SERVICE);
audio.setMode(AudioManager.MODE_IN_COMMUNICATION);
m_AudioGroup = new AudioGroup();
m_AudioGroup.setMode(AudioGroup.MODE_NORMAL);
m_AudioStream = new AudioStream(InetAddress.getByAddress(getLocalIPAddress ()));
int localPort = m_AudioStream.getLocalPort();
m_AudioStream.setCodec(AudioCodec.PCMU);
m_AudioStream.setMode(RtpStream.MODE_NORMAL);
((TextView)findViewById(R.id.lblLocalPort)).setText(String.valueOf(localPort));
((Button) findViewById(R.id.button1)).setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
String remoteAddress = ((EditText)findViewById(R.id.editText2)).getText().toString();
String remotePort = ((EditText)findViewById(R.id.editText1)).getText().toString();
try {
m_AudioStream.associate(InetAddress.getByName(remoteAddress), Integer.parseInt(remotePort));
} catch (NumberFormatException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (UnknownHostException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
m_AudioStream.join(m_AudioGroup);
}
});
((Button) findViewById(R.id.button2)).setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
m_AudioStream.release();
}
});
} catch (Exception e) {
Log.e("----------------------", e.toString());
e.printStackTrace();
}
}
public static byte[] getLocalIPAddress () {
byte ip[]=null;
try {
for (Enumeration<NetworkInterface> en = NetworkInterface.getNetworkInterfaces(); en.hasMoreElements();) {
NetworkInterface intf = en.nextElement();
for (Enumeration<InetAddress> enumIpAddr = intf.getInetAddresses(); enumIpAddr.hasMoreElements();) {
InetAddress inetAddress = enumIpAddr.nextElement();
if (!inetAddress.isLoopbackAddress()) {
ip= inetAddress.getAddress();
}
}
}
} catch (SocketException ex) {
Log.i("SocketException ", ex.toString());
}
return ip;
}
}
布局文件:
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:tools="http://schemas.android.com/tools"
android:id="@+id/LinearLayout1"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:orientation="vertical"
android:paddingBottom="@dimen/activity_vertical_margin"
android:paddingLeft="@dimen/activity_horizontal_margin"
android:paddingRight="@dimen/activity_horizontal_margin"
android:paddingTop="@dimen/activity_vertical_margin"
tools:context=".MainActivity" >
<TextView
android:id="@+id/lblLocalPort"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/localPort" />
<EditText
android:id="@+id/editText2"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginTop="20dp"
android:ems="10"
android:hint="@string/iPHint"
android:inputType="phone" />
<EditText
android:id="@+id/editText1"
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginTop="20dp"
android:ems="10"
android:hint="@string/portHint"
android:inputType="number" >
<requestFocus />
</EditText>
<LinearLayout
android:layout_width="match_parent"
android:layout_height="wrap_content"
android:layout_marginTop="20dp">
<Button
android:id="@+id/button1"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/connect" />
<Button
android:id="@+id/button2"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/Disconnect" />
</LinearLayout>
</LinearLayout>
编辑:IP地址方法在API 22处停止工作，请使用以下代码:
The IP address method stopped working at API 22, use below code:
private byte[] getLocalIPAddress() {
byte[] bytes = null;
try {
// get the string ip
WifiManager wm = (WifiManager) getSystemService(WIFI_SERVICE);
String ip = Formatter.formatIpAddress(wm.getConnectionInfo().getIpAddress());
// convert to bytes
InetAddress inetAddress = null;
try {
inetAddress = InetAddress.getByName(ip);
} catch (UnknownHostException e) {
e.printStackTrace();
}
bytes = new byte[0];
if (inetAddress != null) {
bytes = inetAddress.getAddress();
}
} catch (Exception e) {
e.printStackTrace();
Toast.makeText(this, R.string.phone_voip_incompatible, Toast.LENGTH_SHORT).show();
}
return bytes;
}
这篇关于Android VOIP应用程序，无法访问互联网的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
