如何在android中验证密码字段? [英] How to validate Password Field in android?
本文介绍了如何在android中验证密码字段?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我是android的新手,在我的应用中,我有更改密码验证"页.
Hi I am very new for android and in my app I have Validations for Change password page.
这意味着密码必须至少包含8个字符,至少1个字母,1个数字和1个特殊字符,为此,我尝试了下面的代码,但它不起作用.
That means the Password must contain minimum 8 characters at least 1 Alphabet, 1 Number and 1 Special Character, for this I tried the code below, but it's not working.
请帮助我.
if(!isPasswordValidMethod(newPassword.getText().toString())){
System.out.println("Not Valid");
}else{
System.out.println("Valid");
}
// Validate password
private boolean isPasswordValidMethod(String password) {
String yourString = newPassword.getText().toString();
System.out.println("yourString is =" + yourString);
boolean isValid = false;
// ^[_A-Za-z0-9-\+]+(\.[_A-Za-z0-9-]+)*@[A-Za-z0-9-]+(\.[A-Za-z0-9]+)*(\.[A-Za-z]{2,})$
// ^[\\w\\.-]+@([\\w\\-]+\\.)+[A-Z]{2,4}$
String expression = "^(?=.*[A-Za-z])(?=.*\\\\d)(?=.*[$@$!%*#?&])[A-Za-z\\\\d$@$!%*#?&]{8,}$";
CharSequence inputStr = password;
Pattern pattern = Pattern.compile(expression, Pattern.CASE_INSENSITIVE);
Matcher matcher = pattern.matcher(inputStr);
if (matcher.matches()) {
System.out.println("if");
isValid = true;
}else{
System.out.println("else");
}
return isValid;
}
推荐答案
尝试执行以下代码
//*****************************************************************
public static boolean isValidPassword(final String password) {
Pattern pattern;
Matcher matcher;
final String PASSWORD_PATTERN = "^(?=.*[0-9])(?=.*[A-Z])(?=.*[@#$%^&+=!])(?=\\S+$).{4,}$";
pattern = Pattern.compile(PASSWORD_PATTERN);
matcher = pattern.matcher(password);
return matcher.matches();
}
并将您的代码更改为此
if(newPassword.getText().toString().length()<8 &&!isValidPassword(newPassword.getText().toString())){
System.out.println("Not Valid");
}else{
System.out.println("Valid");
}
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