Android BroadcastReceiver onReceive()在android 4.0上被调用了两次 [英] Android BroadcastReceiver onReceive() called twice on android 4.0

问题描述

我在android 4.0.3上遇到了一个问题(在4.1.2上工作正常). 我的活动BroadcastReceiver中有.当我发送广播时，方法onReceive()总是调用两次.请给我有关4.0和4.1上的BroadcastReceiver差异的任何建议

I faced to one problem on android 4.0.3 (on 4.1.2 it works fine). I have in my Activity BroadcastReceiver. When I send a broadcast, method onReceive() called always twice. Please give me any suggestions about BroadcastReceiver differences on 4.0 and 4.1

private final GcmBroadcastReceiver gcmReceiver = new GcmBroadcastReceiver() {

    @Override
    public void onReceive(Context context, Intent intent) {
        final String action = intent.getAction();
        if (action != null && action.equals(MyBroadcastReceiver.ACTION)) {
            Log.d("tag", intent.getStringExtra("alert"));
            }
        }
    };

};


@Override
protected void onPause() {
    unregisterReceiver(gcmReceiver);
    super.onPause();
}

@Override
protected void onResume() {
    super.onResume();
    registerGcmReceiver();
}

private void registerGcmReceiver() {
    IntentFilter filter = new IntentFilter(MyBroadcastReceiver.ACTION);
    filter.setPriority(2);
    filter.addCategory("com.android.mypackage");
    registerReceiver(gcmReceiver, filter);
}

推荐答案

简短的回答:没有区别.两者的BroadcastReceiver类来自Android 2.3.2 r1.

Short answer: there isn't a difference. The BroadcastReceiver class for both is from Android 2.3.2 r1.

我也遇到过类似的问题，但对我来说，这是安装了Android 2.3.5的HTC Desire HD-来自GCM的通知将始终收到两次.我没有找到问题的根源，但是有一种解决方法.您可以为服务器中的每个通知生成唯一的ID，并将其与实际数据一起发送.然后，在您的接收器中，您可以更新唯一ID与通知数据的映射，如果给定ID已存在数据，则将其忽略.

I've had a similar problem, but for me it was with an HTC Desire HD with Android 2.3.5 on it - the notifications from GCM would always get received twice. I didn't manage to find the root of the problem, but there is a workaround. You can generate a unique ID for each notification in the server and send it along with the actual data. Then, in your receiver, you can update a mapping of unique ID to notification data, and if there is already data for the given ID, just ignore it.

我可能不太清楚，所以这是一个例子:

I probably didn't make that very clear, so here's an example:

public void onReceive(Context context, Intent intent) {
    String id = intent.getStringExtra("notificationID");
    if (myMap.get(id) != null)
        return;

    final String action = intent.getAction();
    if (action != null && action.equals(MyBroadcastReceiver.ACTION)) {
        Log.d("tag", intent.getStringExtra("alert"));
        myMap.put(id, *any value you need*);
    }
}

如果您不需要存储其他数据，则可以使用HashSet代替Map，只需检查其中是否包含ID.

If you don't need to store additional data, you can use a HashSet instead of a Map and just check if it contains the ID.

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