更改属性后重新构建/重新渲染Angular2组件 [英] ReBuild/Re-render Angular2 component when property is changed

查看:107
本文介绍了更改属性后重新构建/重新渲染Angular2组件的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

如何说明这一点?

我的子组件

 import {Component,Input,ngOnInit} from 'angular2/core';

@Component({
selector: 'my-component',
template: `
    <div>In child component - myAttr = {{ myAttr1 }}</div>
`
})
export class MyComponent  {
  @Input() myAttr: number;
  myAttr1:number;
 ngOnInit()
 {
  this.myAttr1=this.myAttr*10;
 }

}

主要组件

import {Component} from 'angular2/core';
import {MyComponent} from './sub.component';

@Component({
selector: 'my-app',
template: `
    <my-component
        [(myAttr)]="myAttr"
    ></my-component>
    <button (click)="onClick()">Click</button>
`,
directives: [MyComponent]
})
export class AppComponent {
   myAttr: number = 1;

  onClick() {
    console.log('Click in the parent component');
    this.myAttr += 1;
  }
}

我需要更新每次点击的值.应该有直接的方法,否则Angular2团队应该考虑一下

I need to update the value in each click. There should be a direct approach , else Angular2 team should think about this

推荐答案

您应该使用ngOnChanges来检测子组件中myAttr的更新时间:

You should use ngOnChanges to detect when myAttr is updated in your sub component:

@Component({
  selector: 'my-component',
  template: `
    <div>In child component - myAttr = {{ myAttr1 }}</div>
  `
})
export class MyComponent  {
  @Input() myAttr: number;
  myAttr1:number;
  ngOnInit() {
    this.myAttr1=this.myAttr*10;
  }

  ngOnChanges() { // <------
    this.myAttr1=this.myAttr*10;
  }
}

这可以检测到myAttr输入属性何时更新,并相应地更新myAttr1一个.

This allows to detect when the myAttr input property is updated and update accordingly the myAttr1 one.

查看此插件: https://plnkr.co/edit/2SOdq7w3s8iDxBKbiLpU?p=preview .

这篇关于更改属性后重新构建/重新渲染Angular2组件的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

查看全文
登录 关闭
扫码关注1秒登录
发送“验证码”获取 | 15天全站免登陆