类型"Observable< {}>"上不存在属性"next" [英] Property 'next' does not exist on type 'Observable<{}>'

问题描述

尝试执行以下操作

let o = new Observable() ;
o.delay( 3000 ).next( { stuff } ) ;

出现以下错误

[ts]属性"next"在类型"Observable< {}>"上不存在

[ts] Property 'next' does not exist on type 'Observable<{}>'

也尝试过

Let o = new Subject(); 
o.delay( 3000 ).next( { stuff } ) ;

仍然得到

[ts]属性"next"在类型"Observable< {}>"上不存在.

[ts] Property 'next' does not exist on type 'Observable<{}>'.

推荐答案

您需要在Subject实例上调用next.然后，示例中的o变量是Subject与返回Observable的运算符链接在一起.

You need to call next on the Subject instance. The o variable from your example is then the Subject chained with the operator that returns an Observable.

const s = new Subject(); 
const o = s.delay(3000);

o.subscribe(...);

s.next();

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