将Json映射到角度对象 [英] Map Json to object in angular
本文介绍了将Json映射到角度对象的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有以下JSON数据
{
"columns": [
{
"table": "black_list",
"name": "id",
"datatype": "uuid"
},
{
"table": "black_list",
"name": "emailid",
"datatype": "varchar"
},
{
"table": "black_list",
"name": "membershipid",
"datatype": "varchar"
},
{
"table": "black_list",
"name": "phonenumber",
"datatype": "varchar"
}
],
"rows": [
{
"id": "59525ac0-9799-11e8-8ea0-897582b5513d",
"emailid": "bid@email.com",
"membershipid": "999999",
"phonenumber": "1234567890"
}
]
}
我的模型是
export interface BlacklistData {
id: string;
emailid: string;
membershipid: string;
phonenumber: string;
}
最后,我使用下面的代码从REST API中获取结果,并尝试将其映射到我的对象
and finally I am using the below code to fetch the result from the REST API and trying to map it to my object
public GetBlackListData(): Observable<WatchlistData[]> {
var path = "http://ec2compute/BDEServices/RestSearch?selectCls=all&fromCls=demo.black_list";
return this.http.get(path)
.pipe(map((result: Response) => this.BlackListData = result.json()));
}
我只想使用JSON数据的行部分来映射到我的对象,我不确定该怎么做.有人可以告诉我如何选择性地解析JSON数据并将其映射到我的对象.
I only want to use the rows part of the JSON data to map to my object and I am not sure how I can do that. Can someone please tell me how to selectively parse JSON data and map it to my object.
我正在使用Angular 6,并从'rxjs/internal/Observable'导入{Observable};
I am using Angular 6 and import { Observable } from 'rxjs/internal/Observable';
谢谢
推荐答案
只需从组件中订阅服务方法,
Just subscribe to your service method from your component as,
this.yourService.GetBlackListData().subscribe(result => this.result =result.rows);
您的模型应如下所示,
export interface Column {
table: string;
name: string;
datatype: string;
}
export interface Row {
id: string;
emailid: string;
membershipid: string;
phonenumber: string;
}
export interface BlacklistData {
columns: Column[];
rows: Row[];
}
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