垫菜单和按钮在不同的组件中 [英] mat-menu and button in different components

问题描述

我有

<mat-menu #saveMenu="matMenu">...</mat-menu>

位于应用程序保存文档组件中，并且

in app-save-document component and

<app-save-document></app-save-document>
<button mat-icon-button [matMenuTriggerFor]="saveMenu">

在另一个组件中.

如果我在不同的组件中具有[matMenuTriggerFor]的菜单和按钮，我可以做些什么来使按钮看到菜单吗?

if I have mat-menu and button with [matMenuTriggerFor] in different components, can I do something to make the button see the menu?

现在我有ERROR Error: mat-menu-trigger: must pass in an mat-menu instance.

推荐答案

好吧，如果您想执行以下操作:

Well, if you want to do something like this:

<button mat-button [matMenuTriggerFor]="menu">Menu</button>
<other-component [matMenu]="menu"></other-component>
<mat-menu #menu="matMenu">
  <button mat-menu-item>Item 1</button>
  <button mat-menu-item>Item 2</button>
</mat-menu>

您可以这样编码<other-component>:

import {Component,Input} from '@angular/core';
import {MatMenu} from '@angular/material';

@Component({
  selector: 'other-component',
  template: `
    This button is in another component:
    <button [matMenuTriggerFor]="matMenu">Click here to open menu</button>
  `,
})
export class OtherComponent {
  @Input() matMenu: MatMenu;
}

您可以在 stackblitz演示中看到上述示例.

---

You can see the above example working at this stackblitz demo.

---

另一种方法是(我想这就是您想要的):您的触发按钮是在父级内部(但在子级外部)并且菜单本身是在子组件中定义的.

Another approach is (I think this is what you want): your trigger button is inside the parent (but outside the child) and the menu itself is defined inside the child component.

父组件:

<button mat-button [matMenuTriggerFor]="childComponentMenu?.menu">
    Menu in other component
</button>
<child-component></child-component>

export class ParentComponent {
  @ViewChild(ChildComponent) childComponentMenu: ChildComponent;
}

子组件:

@Component({
  selector: 'child-component',
  template: `
    <mat-menu>
      <button mat-menu-item>Item 1 (inside other component)</button>
      <button mat-menu-item>Item 2 (inside other component)</button>
    </mat-menu>
  `,
})
export class ChildComponent {
  @ViewChild(MatMenu, {static: true}) menu: MatMenu;
}

---

另一种方法，类似于上述方法，但使用模板引用变量(请注意子组件装饰器中的exportAs):

Another approach, similar to the above one, but using template reference variables (notice the exportAs in the decorator of the child component):

父组件:

<button mat-button [matMenuTriggerFor]="x.menu">
    Menu in other component
</button>
<child-component #x="menuInOtherComponent"></child-component>

export class ParentComponent {
}

子组件:

@Component({
  selector: 'child-component',
  template: `
    <mat-menu>
      <button mat-menu-item>Item 1 (inside other component)</button>
      <button mat-menu-item>Item 2 (inside other component)</button>
    </mat-menu>
  `,
  exportAs: 'menuInOtherComponent',
})
export class ChildComponent {
  @ViewChild(MatMenu, {static: true}) menu: MatMenu;
}

Stackblitz演示

这篇关于垫菜单和按钮在不同的组件中的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！