在电子中互连ipcRenderer和ipcMain时出错 [英] Error when interconnecting ipcRenderer and ipcMain in electron

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问题描述

我已经在电子中配置了cli角,并且我有一个链接可以执行使ipcRenderer和ipcMain互通的功能:

I have configured cli angular in electron, and I have a link where it execute a function that intercomunicate ipcRenderer and ipcMain:

html:

<a (click)="check()"> click </a>

组件:

constructor(private _e: ElectronService) { }

check () {
   this._e.ipcRenderer.send ('conn', 'round');
   this._e.ipcRenderer.on ('conn-st', (event, args) => {
      console.log (args);
   });
}

main.js(电子):

main.js (electron):

ipcMain.on ('conn', function (event, args) {
  event.sender.send ('conn-st', 'trip');
});

问题在于,当您单击一次时,它会执行一次,但是当您再次单击时,它会连续执行3、4、5,依此类推.

The problem is that when you click once, you do it once, but when you click again it does 3, then 4, 5 and so on continuously.

并在达到11时抛出此错误:

And throws this error upon reaching 11:

(node:23006) Error: Possible EventEmitter memory leak detected. 11 conn-st listeners added. Use emitter.setMaxListeners() to increase limit

如何结束ipcRenderer和ipcMain之间的连接?

How do I end the connection between ipcRenderer and ipcMain?

推荐答案

该错误消息仅表明,已创建11个套接字"(如UNIX中的监听器)的侦听器.每个侦听器都会创建一个唯一的ID,该ID在创建侦听器时会返回.基于此,可以这样删除一个特定的侦听器:

That error message only says, that 11 listeners to a "socket" (like the ones in UNIX) were created. Every listener creates a unique ID which is returned when creating the listener. Based on that, removing one particular listener could be done like this:

// Create a listener.
var myListener = function (event, args) {} 
ipcRenderer.on("channel", myListener);

// Delete only this one by its ID:
ipcRenderer.removeListener("channel", myListener);

但是您也可以删除为套接字创建的所有侦听器,如下所示:

But you can also delete all of the listeners that were created for a socket, like this:

// Create a few listeners.
var myListener0 = function (event, args) {};
var myListener1 = function (event, args) {};
var myListener2 = function (event, args) {};
var myListener3 = function (event, args) {};

//
ipcRenderer.on("channel", myListener0);
ipcRenderer.on("channel", myListener1);
ipcRenderer.on("channel", myListener2);
ipcRenderer.on("channel", myListener3);

// Delete all listeners for socket "channel".
ipcRenderer.removeAllListeners("channel");

Electron文档中也对此进行了介绍,尤其是此处.

This is also covered in the Electron documentation, particularly here.

这篇关于在电子中互连ipcRenderer和ipcMain时出错的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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