如何在指令的Angular 5中使用exportAs在模板中获取其引用? [英] How to use exportAs in Angular 5 on directives to get its reference in the template?

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本文介绍了如何在指令的Angular 5中使用exportAs在模板中获取其引用?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有以下指令:

@Directive({
  selector: '[changeColor]',
  exportAs:'changeColor' 
})
export class ColorDirective {
    constructor(elem: ElementRef, renderer: Renderer2) {
       renderer.setStyle(elem.nativeElement, 'color', 'red');
    }
}

我有以下模板:

<h1 changeColor>Hello</h1>

这将按预期工作,并以红色显示"Hello".但是,当我尝试访问指令的引用时,出现错误.例如,下面的代码:

This works as expected and displays "Hello" in red. But, when I try to access a reference of the directive I get an error. For example, the below code:

<h1 #x=changeColor>Hello</h1>
{{x}}

产生以下错误"There is no directive with "exportAs" set to "changeColor"".我要去哪里错了?

produces the below error "There is no directive with "exportAs" set to "changeColor"". Where am I going wrong?

推荐答案

您没有在第二个片段中应用changeColor指令,因为h1上没有changeColor属性.应该是

You didn't apply the changeColor directive in the second snippet, since there is no changeColor attribute on the h1. It should be

<h1 changeColor #x="changeColor">Hello</h1>

您能解释一下为什么属性选择器应该在[]内吗?

can you explain why the selector of an attribute should be within [ ]

因为这是CSS选择器的语法(与CSS样式表中使用的语法相同):

Because that's the syntax for CSS selectors (the same you're using in a CSS stylesheet):

  • [foo]选择任何具有名为foo的属性的元素
  • .foo选择CSS类名为foo
  • 的任何元素
  • foo选择任何名为foo的元素
  • bar[foo]:not(.baz)选择任何名为bar的元素,该元素具有名为foo的属性,并且没有名为baz的类.
  • [foo] selects any element with an attribute named foo
  • .foo selects any element with a CSS class named foo
  • foo selects any element named foo
  • bar[foo]:not(.baz) selects any element named bar, which has an attribute named foo and doesn't have a class named baz.

这篇关于如何在指令的Angular 5中使用exportAs在模板中获取其引用?的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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