加载@ angular/common/http时出错-angular 2 [英] Error loading @angular/common/http - angular 2
问题描述
我正在尝试在Angular 2中实现服务.
I am trying to implement a service in Angular 2.
服务:
import { Injectable } from '@angular/core';
import { HttpClient } from '@angular/common/http';
import { Observable } from 'rxjs/Observable';
import { BrowserModule } from '@angular/platform-browser';
@Injectable()
export class DemoService {
constructor(private http: HttpClient
) { }
GetData(): Observable<String> {
const baseUrl = 'http://localhost:54037/api/home'; // this part will come from config file in futer
// const url = '?resourceId=' + primaryId + '&showDate=' + selectedDate;
// http://localhost:55174/api/Resource?resourceId=3&showDate=2017-06-06
return this.http
.get<String>(baseUrl);
}
}
组件:
import { Component, OnInit } from '@angular/core';
import { DemoService } from './app.service';
import { BrowserModule } from '@angular/platform-browser';
@Component({
selector: 'my-app',
template: `<h1>Hello {{name}}</h1>`,
})
export class AppComponent implements OnInit {
constructor(private s: DemoService){}
name = 'Angular 2';
ngOnInit(){
console.log("Inidialization completed");
}
}
一切正常,但是一旦我在组件类下的构造函数中创建服务实例,就会在控制台收到错误消息.
Everything works fine but as soon as I create an instance of service in constructor under component class, I get an error at the console.
加载错误 http://localhost:3002/node_modules/@ angular/common/bundles/common.umd.js/http 来自"@ angular/common/http" http://localhost:3002/app/app.service.js
Error loading http://localhost:3002/node_modules/@angular/common/bundles/common.umd.js/http as "@angular/common/http" from http://localhost:3002/app/app.service.js
如果删除构造函数部分,则会得到输出.
If I remove constructor part, I get output.
我需要创建一个Constructor实例,然后调用服务.
I need to create an instance of Constructor and then call service.
我做错什么了吗?
推荐答案
在app.module中导入HttpModule,如下所示
Importing HttpModule in app.module like below
import { HttpModule} from '@angular/http'
和
按如下所示将Http导入服务中
Importing Http in service as below
import { Http, Response} from '@angular/http'
解决了问题.
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