AngularJS:将用户活动发送到服务器 [英] AngularJS : send user activity to server

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问题描述

我想将用户活动发送到服务器,尤其是用户单击了哪个按钮.

I would like to send user activity to server, especially which button user clicked.

我知道我可以这样做.

HTML:

<button type="button" class="btn btn-primary" ng-click="pressA()">A</button>
<button type="button" class="btn btn-primary" ng-click="pressB()">B</button>

JS:

$scope.pressA = function() {
  sendServer("A");
  // Do other things for button A
}

$scope.pressB = function() {
  sendServer("B");
  // Do other things for button B
}

function sendServer(msg) {
  var req = new XMLHttpRequest();
  var params = "msg=" + encodeURIComponent(msg);
  req.open("POST", "/scripts/log");
  req.send(params);
}

但是这种方式要求我将sendServer插入所有ng-click事件.好烦我可以用这种更有效的方法吗?

But this way require me to insert sendServer to all ng-click event. It is bothersome. Can I do this more efficient way?

推荐答案

如果要为定义的每个ng-click执行某些操作,则可以定义一个自定义的ngClick指令来完成此工作.

If you want to execute something for each ng-click you define, you can define a custom ngClick directive to do the job.

.directive('ngClick', function() {
  return {
    restrict: 'A',
    priority: 1, // built-in ngClick has priority 0
    link: function(scope, element, attr) {
      element.on('click', function() {
        // do something
      });
    }
  }
});

但是,这不会涵盖所有操作(aHref,ngSubmit ...).

However, this will not cover every actions (aHref, ngSubmit...).

这篇关于AngularJS:将用户活动发送到服务器的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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