TypeError:$ scope.apply不是一个函数 [英] TypeError: $scope.apply is not a function

问题描述

我正在尝试通过rdflib.js检索联系人列表.它已正确加载，并将其保存在合并范围内的列表中.

I am trying to render the contacts list after retrieving it thru rdflib.js. It is loading properly and saving it in the list inside the scope.

但是我无法渲染$ scope不更新的正弦，似乎我在错误的地方调用了$scope.apply().发生错误是因为我在angular外部调用了它，但是我故意在angular context(nowOrWhenFetched)外部的函数内部调用了它，所以对我来说没有意义.有帮助吗?

But I am not able to render sine the $scope doesn't update, it seems like I am calling $scope.apply() in the wrong place. The error occurs because I call it outside angular, but I am deliberately calling it inside the function that is outside angular context (nowOrWhenFetched), so not making sense for me. any help?

$scope.load = function () {
    //$scope.getContactsList();
    var g = $rdf.graph();
    var f = $rdf.fetcher(g);

    f.nowOrWhenFetched($scope.path + '*',undefined,function(){

    var DC = $rdf.Namespace('http://purl.org/dc/elements/1.1/');
    var RDF = $rdf.Namespace('http://www.w3.org/1999/02/22-rdf-syntax-ns#');
    var LDP = $rdf.Namespace('http://www.w3.org/ns/ldp#');
    //var myOntology = $rdf.Namespace('http://user.pds.org/ontology/'); 
    var VCARD = $rdf.Namespace('http://www.w3.org/2006/vcard/ns#');

    var evs = g.statementsMatching(undefined, RDF('type'), VCARD('Individual'));
    if (evs != undefined) {
        for (var e in evs) {
            var id = evs[e]['subject']['value'];
            var fullname = g.anyStatementMatching(evs[e]['subject'], VCARD('fn'))['object']['value'];
            var email = g.anyStatementMatching(evs[e]['subject'], VCARD('hasEmail'))['object']['value'];
            var phone = g.anyStatementMatching(evs[e]['subject'], VCARD('hasTelephone'))['object']['value'];

            var contact = {
                id: id.slice(id.length-1),
                Name: fullname,
                Email: email,
                Phone: phone 
            };

            $scope.contacts.push(contact);
        }

    }

    $scope.apply();

    });

};

推荐答案

函数为$apply()，带有$.

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