你如何回报新观测（函数（观察员）{...与RxJS V5？ [英] How do you return new Observable(function(observer) { ... with RxJS v5?

问题描述

我想全部更换，我的职能，观测量返回的承诺。从这篇文章中，我才知道，我应该不再使用新的可观察到的<一个href=\"http://stackoverflow.com/questions/35676451/observable-forkjoin-and-array-argument\">Observable.forkJoin和数组参数

I am trying to replace all the promises that my functions return with Observables. From this post, I learned that I should no longer use "new Observable" Observable.forkJoin and array argument

什么是RxJS V5语法来实现这一目标本身来实现异步等待？

What is the RxJS v5 syntax to achieve this as such to achieve asynchronous waiting?

thirdFunction() {

    let _self = this;

    return new Observable(function(observer) {

        ...

        observer.next( responseargs );
        observer.complete();
    });
}

感谢您大为帮助，您可以提供的。

Thank you greatly for help you can offer.

推荐答案

有一组方法来创建不同的使用情况下可观察：

There are a set of methods to create observables for different use cases:

的
• - 创建一个可观察的，并直接引发与提供的值的事件


• 超时 - 创建一个可观察的时间的金额
后触发事件

• 间隔 - 创建一个可观察的时间的金额
后反复触发

• of - create an observable and directly trigger an event with the provided value
• timeout - create an observable that triggers an event after an amount of time
• interval - create an observable that triggers repeatly after an amount of time

此链接按类别为他们提供的列表：

This link provides a list of them by category:

• 的https://github.com/Reactive-Extensions/RxJS/blob/master/doc/gettingstarted/categories.md

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