字符串不匹配时的条件 [英] Ansible condition when string not matching

问题描述

我正在尝试编写Ansible剧本，仅在Nginx不存在且当前版本不存在时才对其进行编译.但是它每次都会编译，这是不希望的.

I am trying to write an Ansible playbook that only compiles Nginx if it's not already present and at the current version. However it compiles every time which is undesirable.

这就是我所拥有的:

- shell: /usr/local/nginx/sbin/nginx -v 2>&1
  register: nginxVersion
- debug:
  var=nginxVersion

- name: install nginx
  shell: /var/local/ansible/nginx/makenginx.sh
  when: "not nginxVersion == 'nginx version: nginx/1.8.0'"
  become: yes

该脚本的工作原理与每次编译Nginx都运行shell脚本的事实不同. nginxVersion的调试输出为:

The script all works apart from the fact that it runs the shell script every time to compile Nginx. The debug output for nginxVersion is:

ok: [server] => {
    "var": {
        "nginxVersion": {
            "changed": true,
            "cmd": "/usr/local/nginx/sbin/nginx -v 2>&1",
            "delta": "0:00:00.003752",
            "end": "2015-09-25 16:45:26.500409",
            "invocation": {
                "module_args": "/usr/local/nginx/sbin/nginx -v 2>&1",
                "module_name": "shell"
            },
            "rc": 0,
            "start": "2015-09-25 16:45:26.496657",
            "stderr": "",
            "stdout": "nginx version: nginx/1.8.0",
            "stdout_lines": [
                "nginx version: nginx/1.8.0"
            ],
            "warnings": []
        }
    }
}

根据我所掌握的文档，我缺少什么简单的窍门?

According to the documentation I am on the right lines, what simple trick am I missing?

推荐答案

尝试:

when: nginxVersion.stdout != 'nginx version: nginx/1.8.0'

或

when: '"nginx version: nginx/1.8.0" not in nginxVersion.stdout'

这篇关于字符串不匹配时的条件的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！