如何在规则中排除多个字符? [英] How to exclude more than one character in rule?

问题描述

我正在尝试在ANTLRWorks中编写一个字符串匹配规则，并且我需要匹配转义的引号或任何非引号字符.我可以匹配转义的引号，但其他部分遇到麻烦:~'\'' | ~'\"'最终将匹配所有内容，并且~'\'\"'似乎被语法生成器忽略(至少是视觉显示).什么字符序列可以让我得到我想要的东西?

I'm trying to write a string matching rule in ANTLRWorks, and I need to match either escaped quotes or any non quote character. I can match escaped quotes but I'm having trouble with the other part: ~'\'' | ~'\"' will end up matching everything and ~'\'\"' seems to be ignored by the grammar generator (at least the visual display). What sequence of characters will get me what I want?

推荐答案

尝试如下操作:

StringLiteral
    :    '"' (EscapeSequence | StringChar)* '"'
    ;

EscapeSequence
    :    '\\' ('"' | '\\')
    ;

StringChar
    :    ~('"' | '\\')
    ;

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