返回当前令牌的最后一个字符的行号 [英] Return the line number of the last character for current token

问题描述

ANTLR 4中是否可以返回当前令牌的最后一个字符的行号?

Is there a way in ANTLR 4 to be able to return the line number of the the last character for the current token ?

我提到了 Antlr，从令牌中获取最后一行，但是那是特定于规则.我想要更通用的东西，但在ANTLR API中找不到适合我的东西.

I referred Antlr, get last line from token but that would be specific to a rule. I wanted something more generic but couldn't find what would suit me in the ANTLR API.

推荐答案

没有直接的方法来获取此信息.但是，如果您的词法分析器中没有任何-> skip命令，则可以从以下标记派生它.

There is no direct way to get this information. However, if you don't have any -> skip commands in your lexer you can derive it from the following token.

假设令牌b跟在令牌a之后.如果为b.getCharPositionInLine()==0，则a的最后一个字符在行b.getLine()-1上.否则，a的最后一个字符在行b.getLine()上.

Suppose token b follows token a. If b.getCharPositionInLine()==0, the last character of a is on line b.getLine()-1. Otherwise, the last character of a is on line b.getLine().

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