在骆驼中，如何在标头上使用xpath拆分路线 [英] In Camel how can i split a route using xpath on a header

问题描述

正如标题所示，我有一条带有标题的路由，该标题包含一些类似于以下代码片段的xml作为字符串；

As the title suggests, i have a route with a header that contains some xml similar to the following snippet as a string;

<files>
  <image_file1>image.png</image_file1>
  <image_file2>image.png</image_file2>
</files>

我正在尝试做的事情是通过xpath使用类似以下内容的方法来拆分的.如下所示，当xml是主体的一部分时，所有命令都可以正常运行:-

What I'm trying do do is split via xpath using something like the following. As the following suggests when the xml is part of the body, all runs fine:-

from(myIncomingQueue)
    .convertBodyTo(String.class, "utf-8")
    .split(xpath("//*[local-name()='files']/*"))
        .setHeader("FilePropertyToRetrieve", xpath("local-name(//*)").stringResult())
        .to(myFileDownloadQueue)
.routeId("COMMON-CON-Attachment_Router-Id");

我使用以下方法找到了解决方案:-

I found a solution using the following:-

from(myIncomingQueue)
    .setBody(header("myHeaderWithXml"))
    .convertBodyTo(String.class, "utf-8")
    .split(xpath("//*[local-name()='files']/*"))
        .setHeader("FilePropertyToRetrieve", xpath("local-name(//*)").stringResult())
        .setBody(header("CamelOriginalBody"))
        .to(myFileDownloadQueue)
.routeId("COMMON-CON-Attachment_Router-Id");

但是出于学习目的，您是否仍然想知道是否有一种方法可以将标头移到主体中，然后再将其反转呢?

But would still like to know for learning purposes, if there is a way to do it without moving the header into the body and then reversing afterwards?

推荐答案

是的，如果您在以下位置阅读了有关xpath的文档: http://camel.apache.org/xpath -然后参见在标题上使用XPath

Yes if you read the docs about xpath at: http://camel.apache.org/xpath - then see the section Using XPath on Headers

类似的东西

  .split(xpath("//*[local-name()='files']/*", "myHeaderWithXml"))

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