如何从视图的局部视图传递模型？ [英] How to pass Model from a view to a partial view?

问题描述

我有一个观点，即是不可以强类型。不过，我在这个认为是强类型的局部视图。

I have a view that is not strongly typed. However I have in this view a partial view that is strongly typed.

我怎么做我通过模型这种强类型的观点？

How do I do I pass the model to this strongly typed view?

我想是这样

 public ActionResult Test()
        {
              MyData = new Data();
              MyData.One = 1;
              return View("Test",MyData)
        }

在我TestView

In my TestView

<% Html.RenderPartial("PartialView",Model); %>

这给我一个计算器例外。所以，我不知道如何通过它。当然，我不希望让测试来看，如果可能的强类型，就好像我有过10强类型的局部视图在该视图我需要像某种包装发生了什么。

This give me a stackoverflow exception. So I am not sure how to pass it on. Of course I don't want to make the test view strongly typed if possible as what happens if I had like 10 strongly typed partial views in that view I would need like some sort of wrapper.

推荐答案

您应该扩展你的模型，以便它可以提供对视图中的所有必要的字段（这就是所谓的视图模型），或者单独为他们提供的ViewData。

You should extend your model so that it can provide all necessary fields for the view (this is called ViewModel) or you provide them seperately with ViewData.

 public ActionResult Test()
        {
              MyData = new Data();
              MyData.One = 1;
              ViewData["someData"]=MyData;
              return View();
        }

然后：

<% Html.RenderPartial("PartialView",ViewData["someData"]); %>

ViewData的是一个很好的losely类型的字典

ViewData is a nice losely typed dictionary

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