Web应用程序中的Appium:无法在通知弹出窗口中点击“允许"按钮 [英] Appium in Web app: Unable to tap Allow permission button in notification pop up window

问题描述

当我打开Web应用程序时，我会弹出一个窗口.我试图通过两种方式单击允许"按钮:

When I am opening the web app, I am getting a pop up. I'm trying to click on 'ALLOW' button in two ways:

1)当我添加权限时:

1) When I add permissions:

caps.setCapability("autoGrantPermissions", true);
caps.setCapability("autoAcceptAlerts", true);
......
driver.switchTo().alert().accept();

什么都没发生((

2)当我尝试通过XPath查找它时:

2) When I try to find it by XPath:

driver.findElement(By.xpath("//android.widget.Button[@text='Allow']")).click();

我得到一个错误:

Exception in thread "main" org.openqa.selenium.NoSuchElementException: no such element: Unable to locate element: {"method":"xpath","selector":"//android.widget.Button[@text='Allow']"}

这是我从UI Automator Viewer中截取的屏幕截图:

This is my screenshot from UI Automator Viewer :

我发现了这篇文章: 但这对我没有帮助.

I found this post:Unable to tap the link after tap on Allow button of permission alert in Appium? but it didn't help me.

推荐答案

首先:您要使用的功能用于

First: capabilities you were trying to use are for IOS only

在Android上，您必须通过findElement找到弹出窗口，然后自行关闭弹出窗口.

On Android you have to find popup via findElement and close them yourself.

第二:由于您启动了网络应用的Appium会话，因此在搜索本机弹出窗口之前，您必须切换上下文:

Second: since you start Appium session for web application, before searching for native popups you must switch the context:

    String webContext = driver.getContext();
    Set<String> contexts = driver.getContextHandles();
    for (String context: contexts){
        if (context.contains("NATIVE_APP")){
            driver.context(context);
            break;
        }
    }
    driver.findElement(By.id("android:id/button1")).click();

别忘了将上下文切换回Web继续:

Don't forget to switch context back to web to continue:

    driver.context(webContext);

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