如何正则表达式匹配整个字符串而不是单个字符 [英] How to regex match entire string instead of a single character

问题描述

我尝试按照

I am trying to implement "alpha" validation on Arabic alphabet characters input, using the JavaScript regex /[\u0600-\u06FF]/ as instructed in this post. I want to accept only Arabic alphabet characters and spaces.

现在的问题是它给出了以下结果:

Now the problem is it gives the following result:

r = /[\u0600-\u06FF]/

r.test("abcd")      // false - correct
r.test("@#$%^")     // false - correct
r.test("س")         // true  - correct
r.test("abcd$$#5س") // true  - should be false
r.test("abcdس")     // true  - should be false

如果给出单个匹配字符，则它将整个输入分类为可接受，即使输入的其余部分充满了不可接受的字符.我应该改用什么正则表达式?

If a single matching character is given, then it is classifying the whole input as acceptable, even if the rest of the input is full of unacceptable chars. What regex should I be using instead?

推荐答案

您需要在正则表达式中添加^和$锚，以及一个+以允许多个字符.

You need to add ^ and $ anchors to the regular expression, as well as a + to allow multiple characters.

尝试一下:

/^[\u0600-\u06FF]+$/

我不确定您提到的阿拉伯语空格"是否包含在该字符范围内，但是如果您想在字符串中允许空格，则只需在[]括号内添加一个\s即可.

I'm not sure if "Arabic spaces" that you mentioned are included in the character range there, but if you want to allow white space in the string then just add a \s inside the [] brackets.

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