如何通过使用C#.NET 4.5将文件从ZIP存档读取到内存,而无需先将其提取到文件中? [英] How to read file from ZIP archive to memory without extracting it to file first, by using C# .NET 4.5?
问题描述
.NET Framework 4.5通过System.IO.Compression
中的类添加了对ZIP文件的支持.
.NET Framework 4.5 added support for ZIP files via classes in System.IO.Compression
.
比方说,我有.ZIP存档,其根目录中有sample.xml
文件.我想直接从存档读取此文件到内存流,然后将其反序列化为自定义.NET对象.最好的方法是什么?
Let's say I have .ZIP archive that has sample.xml
file in the root. I want to read this file directly from archive to memory stream and then deserialize it to a custom .NET object. What is the best way to do this?
推荐答案
从 XmlSerializer.Deserialize()
手册页.
Adapted from the ZipArchive
and XmlSerializer.Deserialize()
manual pages.
ZipArchiveEntry
类具有Open()
方法,该方法将流返回到文件.
The ZipArchiveEntry
class has an Open()
method, which returns a stream to the file.
string zipPath = @"c:\example\start.zip";
using (ZipArchive archive = ZipFile.OpenRead(zipPath))
{
var sample = archive.GetEntry("sample.xml");
if (sample != null)
{
using (var zipEntryStream = sample.Open())
{
XmlSerializer serializer = new XmlSerializer(typeof(SampleClass));
SampleClass deserialized =
(SampleClass)serializer.Deserialize(zipEntryStream);
}
}
}
请注意,正如MSDN上记录的那样,您需要添加对.NET程序集System.IO.Compression.FileSystem
的引用才能使用ZipFile
类.
Note that, as documented on MSDN, you need to add a reference to the .NET assembly System.IO.Compression.FileSystem
in order to use the ZipFile
class.
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