将整数传递给Arduino [英] Pass an integer to an Arduino

问题描述

我在将整数传递给非1或0的Arduino时遇到了一些麻烦.在此示例中，我希望能够传递3.原因是我很快将拥有更多控制按钮的不同部分的按钮. Arduino，并且将需要不同的整数值来执行此操作.

I am having some trouble passing over integers to the Arduino that is not a 1 or a 0. In this example I want to be able to pass a 3. The reason is that I will soon have more buttons controlling different parts of the Arduino and will need different integer values to do this.

这是Arduino代码.

Here is Arduino code..

void setup()
{
  Serial.begin(9600);
  // Define the led pin as output
  pinMode(13, OUTPUT);
}
void loop()
{
  // Read data from serial communication
  if (Serial.available() > 0) {
  int b = Serial.read();
  // Note, I made it so that it's more sensitive to 0-40% load.
  // Since thats where it's usually at when using the computer as normal.

if (b == 3)
{
  digitalWrite(13, HIGH);
}
else if (b == 0)
{
  digitalWrite(13, LOW);
}

Serial.flush();
}
}

这是我的C#代码.

    int MyInt = 3;
    byte[] b = BitConverter.GetBytes(MyInt);


    private void OnButton_Click(object sender, EventArgs e)
    {
        serialPort1.Write(b, 0, 4);
    }
    private void OffButton_Click(object sender, EventArgs e)
    {
        serialPort1.Write(new byte[] { Convert.ToByte("0") }, 0, 1);
    }

我有两种通过串行端口发送数据的方式，但是它们都以相同的方式工作.我的问题是我如何知道Arduino端Serial.read()的值是什么.当我选择要发送的C#程序中不是1或0的任何值(例如3)时，该程序将无法工作.显然，没有将3作为3发送到Arduino来存储为整数值.

I have two different ways of sending data through the serialport, but they both work in the same way. My question is how do I know what values are coming out of the Serial.read() at the Arduino side. When I choose any value that is not a 1 or a 0 in my C# program to send, such as a 3, the program does not work. Clearly 3 is not being sent over as 3 to the Arduino to be stored into an integer value.

推荐答案

我略微修改了您的代码-int b作为顶部的声明被拉出， 我改变了你的行b = Serial.read();到b = Serial.read()-'0';

I modified your code slightly - int b is pulled out as a declaration at the top, and I changed your line b = Serial.read(); to b = Serial.read() - '0';

int b;

void setup()
{
  Serial.begin(9600);
  // Define the led pin as output
  pinMode(13, OUTPUT);
}
void loop()
{
// Read data from serial communication
if (Serial.available() > 0) {

b = Serial.read() - '0';
// Note, I made it so that it's more sensitive to 0-40% load.
// Since thats where it's usually at when using the computer as normal.

if (b == 3)
{
  digitalWrite(13, HIGH);
}
else if (b == 0)
{
  digitalWrite(13, LOW);
}

Serial.flush();

} }

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