Java地址簿.如何防止我的代码中重复的联系人? [英] Java address book. How to prevent duplicate contacts in my code?
本文介绍了Java地址簿.如何防止我的代码中重复的联系人?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
switch(menuChoice) {
case 1:
System.out.println("Enter your contact's first name:\n");
String fname = scnr.next();
System.out.println("Enter your contact's last name:\n");
String lname = scnr.next();
Necronomicon.addContact(new Person(fname, lname));
break;
// main truncated here for readability
import java.util.ArrayList;
public class AddressBook {
ArrayList<Person> ArrayOfContacts= new ArrayList<Person>();
public void addContact(Person p) {
ArrayOfContacts.add(p);
/*
for(int i = 0; i < ArrayOfContacts.size(); i++) {
if(ArrayOfContacts.get(i).getID() != p.getID())
ArrayOfContacts.add(p);
else
System.out.println("Sorry this contact already exists.");
}
*/
}
}
public class Person {
private String fName = null;
private String lName = null;
private static int ID = 1000;
public Person(String fName, String lName) { // Constructor I'm using to try and increment the ID each time a Person object is created starting at 1001.
this.fName = fName;
this.lName = lName;
ID = ID + 1;
}
}
我正在尝试创建一个通讯录,其中每个联系人都有一个名字,姓氏和唯一的ID.
I am trying to create an address book whereby each contact has a first name, last name and a unique ID.
我的问题是如何防止用户输入具有相同名字和姓氏的重复联系人?我应该在addContact方法中还是在main中实现某种检查?如何?
My question is how to I prevent a user from entering in duplicate contacts with the same first and last name? Should I implement some kind of check in the addContact method or right in main? How?
推荐答案
此处是用于保留重复ID的代码.
Here is the code for keeping out duplicate ID's.
public void addContact(Person p) {
for(int i = 0; i < ArrayOfContacts.size(); i++) {
Person contact = ArrayOfContacts.get(i);
if(contact.getID() == p.getID()) {
System.out.println("Sorry this contact already exists.");
return; // the id exists, so we exit the method.
}
}
// Otherwise... you've checked all the elements, and have not found a duplicate
ArrayOfContacts.add(p);
}
如果您想更改此代码以保留重复的名称,请执行以下操作
If you would like to change this code to keep out duplicate names, then do something like this
public void addContact(Person p) {
String pName = p.getFname() + p.getLname();
for(int i = 0; i < ArrayOfContacts.size(); i++) {
Person contact = ArrayOfContacts.get(i);
String contactName = contact.getFname() + contact.getLname();
if(contactName.equals(pName)) {
System.out.println("Sorry this contact already exists.");
return; // the name exists, so we exit the method.
}
}
// Otherwise... you've checked all the elements, and have not found a duplicate
ArrayOfContacts.add(p);
}
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