Bash-仅在出现换行时转到下一个索引，而不是空格? [英] Bash - Only go next index when new line occurs, instead of white space?

问题描述

我正在使用名为jq的工具解析JSON响应. jq的输出将为我提供命令行中的全名列表.

I'm parsing a JSON response with a tool called jq. The output from jq will give me a list of full names in my command line.

我有一个变量 getNames ，其中包含JSON，例如:

I have the variable getNames which contains JSON, for example:

{
    "count": 49,
    "user": [{
        "username": "jamesbrown",
        "name": "James Brown",
        "id": 1
    }, {
        "username": "matthewthompson",
        "name": "Matthew Thompson",
        "id": 2
    }]
}

我通过以下命令将其传递给JQ以过滤json:

I pass this through JQ to filter the json using the following command:

echo $getNames | jq -r .user[].name

哪个给我这样的列表:

James Brown   
Matthew Thompson   

我想将这些条目中的每一个放入bash数组中，所以我输入以下命令:

I want to put each one of these entries into a bash array, so I enter the following commands:

declare -a myArray    
myArray=( `echo $getNames | jq -r .user[].name` )

但是，当我尝试使用以下命令打印阵列时:

However, when I try to print the array using:

printf '%s\n' "${myArray[@]}"

我得到以下信息:

James
Brown
Matthew
Thompson

如何确保在新行之后而不是空格之后创建新索引?为什么要分隔名称?

How do I ensure that a new index is created after a new line and not a space? Why are the names being separated?

谢谢.

推荐答案

bash中的一个简单脚本，用于将输出的每一行馈入数组myArray.

A simple script in bash to feed each line of the output into the array myArray.

#!/bin/bash

myArray=()
while IFS= read -r line; do
    [[ $line ]] || break  # break if line is empty
    myArray+=("$line")
done < <(jq -r .user[].name <<< "$getNames")

# To print the array
printf '%s\n' "${myArray[@]}"

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