为什么我的程序接受一个整数太多而输入一个太少? [英] Why does my program accept one integer too many and input one too few?

问题描述

我想了解为什么当我将SIZE定义为2时，程序允许我输入3个整数.返回数组时，它仅返回两个数字而不是我输入的三个数字.感谢您的帮助./p>

I'd like to understand why the program allows me to input 3 integers when I have defined SIZE as 2. And when it returns the array it only returns two numbers NOT the three I have entered.Thanks for your help.

//C How to Program Exercises 2.23
#include <stdio.h>
#include <conio.h>
#define SIZE 2

int main (void){

    int myArray[SIZE];
    int count;
    printf("Please enter 5 integers\n");
    for (count=1;count<=SIZE;count++){
        scanf("%d\n",&myArray[count]);
    }
    for (count=1;count<=SIZE;count++){
        printf("The values of myArray are %d\n",myArray[count]);
    }
    getch();

    return 0;
}

推荐答案

您的循环应该是

for (count=0;count<SIZE;count++)

数组索引是基于C的0.

由于在scanf()调用中有一个空白字符(\n)，它将等待您输入一个非空白字符以完成每个调用.删除\n:

Since you have a whitespace chatacter (\n) in scanf() call, it waits for you input a non-whitespace character to complete each call. Remove the \n:

   for (count=0;count<SIZE;count++){
    scanf("%d",&myArray[count]);
}

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