从调用了forEach()数组方法的方法返回.的JavaScript [英] Return from a method in which forEach() array method was called. JavaScript

问题描述

我正在使用从JavaScript中的数组调用的forEach()方法.当我在为数组中每个元素调用的方法内部写入return;时，我从为特定元素调用的方法中退出，仅此而已.但是我真正想要的是从名为forEach()的数组的方法中退出.这是代码:

I am using forEach() method called from an array in JavaScript. When I write return; somewhere inside the method which is called for every element in array I return out from the method which was called for a specific element and that is all. But what I actually want is to return out from the method in which array called forEach(). Here is the code:

    function addToCart(pizza, size)
    {
        Cart.forEach(function(cartItem)
        {
            if(pizzaAndSizeAreTheSame(cartItem, pizza, size))
            {
                cartItem.quantity++;
                updateCart();
                //Want go out from addToCart if this return is reached
                return;
            }
        });

        //Don`t want the code run after return;
        Cart.push
        ({
            pizza: pizza,
            size: size,
            quantity: 1
        });
        updateCart();
    }

这是到目前为止我提出的解决方案:

Here is solution with which I came up so far :

    function addToCart(pizza, size)
{
    var leaveTheMethod = false;
    Cart.forEach(function(cartItem)
    {
        if(pizzaAndSizeAreTheSame(cartItem, pizza, size))
        {
            cartItem.quantity++;
            updateCart();
            leveTheMethod = true;
        }
    });
    if(leaveTheMethod)
        {return;}

    //Don`t want the code run after return;
    Cart.push
    ({
        pizza: pizza,
        size: size,
        quantity: 1
    });
    updateCart();
}

我想知道是否有更好的解决方案.

I would like to know are there any better solutions to the problem.

与该问题相比:如何使Array短路. forEach喜欢打电话吗? 我对了解forEach()循环中的新方法不感兴趣，并且我不想打破forEach()，而是摆脱包含forEach()调用者方法的问题.

Compared to that question: How to short circuit Array.forEach like calling break? I am not interested in knowing the new method in forEach() loop and I want to break not from forEach() but from encompassing the forEach() caller method.

推荐答案

function addToCart(pizza, size) {
    var res = Cart.some(function(cartItem)) {
        if(pizzaAndSizeAreTheSame(cartItem, pizza, size)) {
            cartItem.quantity++;
            updateCart();
            //Want go out from addToCart if this return is reached
            return true;
        }
        return false;
    });

    if(res) {
      return;
    }
    //Don`t want the code run after return;
    Cart.push({
        pizza: pizza,
        size: size,
        quantity: 1
    });
    updateCart();
}

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