在多个字段上进行数组过滤 [英] Array filtering on multiple fields

问题描述

我有这段代码可以过滤我的数据.我问我，是否有一种方法不显式过滤每个字段(id，mandant，zonenlogik ...). 也许有一种更平滑的方法可以在所有字段上设置过滤器，而无需显式调用它们?

I have this code, which filters my data. I'm asking me, if there is a way not to filter each field (id, mandant, zonenlogik...) explicitly. Maybe there is a more smooth way to set the filter on all fields without calling them explicitly?

let filteredList = this.state.freights.filter((freight) => {

    if (freight.id.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.mandant.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.zonenlogik.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.frachtart_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.transportart_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.spedit_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.spedit2_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
    if (freight.lager_nr.toLowerCase().indexOf(this.state.search.toLowerCase()) !== -1) {
        return freight;
    }
});

推荐答案

您可以使用Object.values()获取对象值，然后遍历这些值以检查字符串中是否存在子字符串，然后返回已过滤的对象

You can fetch the object values using Object.values() and then loop over those to check whether a substring is present in the string and then return the filtered object

let filteredList = this.state.freights.filter((freight) => {
    let search = this.state.search.toLowerCase();
    var values = Object.values(freight);
    var flag = false
    values.forEach((val) => {
      if(val.toLoweCase().indexOf(search) > -1) {
           flag = true;
           return;
       }
     }
     if(flag) return freight
});

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