如何检查一个游戏对象是否可以看到另一个? [英] How can I check if one game object can see another?

问题描述

我有一个物体，该物体面向特定方向，例如(45度)视野和一个极限视野范围.我已经完成了所有的初始检查(四叉树节点和距离)，但是现在我需要检查某个特定对象是否在该视锥内(在这种情况下，如果可以看到，则决定只跟随该对象).

I have an object, that is facing a particular direction with (for instance) a 45 degree field of view, and a limit view range. I have done all the initial checks (Quadtree node, and distance), but now I need to check if a particular object is within that view cone, (In this case to decide only to follow that object if we can see it).

除了为从Direction - (FieldOfView / 2)到Direction + (FieldOfView / 2)的每个度数投射射线(目前我正在这样做，这很可怕)之外，进行此可见性检查的最佳方法是什么?

Apart from casting a ray for each degree from Direction - (FieldOfView / 2) to Direction + (FieldOfView / 2) (I am doing that at the moment and it is horrible), what is the best way to do this visibility check?

推荐答案

计算视图方向(理解为矢量)与以您为起点并以对象为终点的矢量之间的角度.如果它属于FieldOfView/2，则可以查看该对象.

Compute the angle between your view direction (understood as a vector) and the vector that starts at you and ends at the object. If it falls under FieldOfView/2, you can view the object.

那个角度是:

arccos(scalarProduct(viewDirection, (object - you)) / (norm(viewDirection)*norm(object - you))).

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