在python中以设置的宽度打印ASCII菱形 [英] Printing an ASCII diamond with set width in python

问题描述

是的，这是一项家庭作业.但是请，如果您要给我代码，请告诉我您已完成的详细操作.我对此很陌生.

Yes, this is a homework task. But just please, if you're going to give me the code please tell me what you've done in detail. I am extremely new to this.

因此，任务是根据用户输入的宽度来打印ASCII菱形.我可以做钻石的上半部分，而不能做钻石的下半部分，由于某种原因，我只是看不到该怎么做.

So the task is to print an ASCII diamond depending on what width the user inputs. I can do the first half of the diamond, just not the bottom half, for some reason I just cannot see how to do it.

这是我的代码:

wid = int(input("Width: "))
i = 1

while i <= wid:
  print(" " * (wid - i) + "* " * i)
  i = i + 1

如果wid = 5，将输出以下内容:

Which will output the following if wid = 5:

Width: 5
    * 
   * * 
  * * * 
 * * * * 
* * * * * 

推荐答案

 i=1
 j=input("ENTER NO =")
 l=0
 for i in range(i,j-((j/2)-1),1):
     print (' ' * ((j+1)/2-i)+'*' *(i*2-1))
     l=(j/2+1)
     while  (i==l):
        i=1
        for i in range(i,j,1):
            print (' ' *((i*2)-i)+'*' *(j-i*2))
        if [i==j-1]:
            l=raw_input('<press enter to exit>')       

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