在Swift 3中比较字符串会得出错误的结果(Linux) [英] Comparing Strings in Swift 3 gives false results (Linux)

问题描述

我不明白Swift比较字符串的方式.

I don't understand the way Swift compares strings.

在Linux上为Swift(3.0.2):

Swift (3.0.2) on Linux:

print("2" < "=") //returns false

，但其他语言(例如Ruby):

but other languages such as Ruby:

p("2:" < "=:") #returns true

似乎我们应该迅速返回true，因为"2"以ASCII顺序出现在"="之前.是错误还是我错过了什么?

It seems we should have swift returning true since "2" comes before "=" in ASCII order. Is it a bug or do I miss something?

推荐答案

从注释中看，您似乎仅在Linux上对此进行了测试. Swift在Linux上如何处理字符排序方面存在一个未解决的错误，请参见 SR-530

From the comments, it seems that you are testing this on Linux only. There is an open bug how Swift handles char ordering on Linux, see SR-530

原始答案:

Ruby的p返回作为其参数传递的对象.

Ruby's p returns object passed as its argument.

等效比较将是Ruby puts与Swift print.两者都(几乎)不返回任何内容.

Equivalent comparison would be Ruby puts vs Swift print. Both return (almost) nothing.

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