引用NSURL中的字符串 [英] Referencing a string inside an NSURL
本文介绍了引用NSURL中的字符串的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我正在尝试在此NSURL中使用此字符串,但是我认为它不正确,从而给我一个ASI HTTP请求失败错误.
I'm trying to use this string inside this NSURL however I don't think its right and in turn giving me an ASI HTTP request failed error.
NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"https://furious-ice-356.heroku.com/places/%@/reviews.xml",self.identifier]];
推荐答案
self.identifier
返回(在大多数情况下)类型为id
的对象.您不能将此对象投射到NSString*
.
self.identifier
returns (in most cases) an object of the type id
. You cannot cast this object to a NSString*
.
唯一的例外是NSUserInterfaceItemIdentification
协议中10.7新引入的NSString*
的identifier
属性.
The only exception is the in 10.7 newly introduced identifier
property of NSString*
in the NSUserInterfaceItemIdentification
protocol.
您能否详细说明问题,以便我们了解self
具有什么类型?
Can you elaborate your question so we can see what type self
has?
这篇关于引用NSURL中的字符串的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!
查看全文