以小写形式返回函数名称 [英] Return the name of a function in lowercase

问题描述

在我的项目(ASP.net MVC)中，我必须返回功能的名称(我读入的CSV文件) 小写.因为现在我已经将函数分组，并且它以相同的名称返回函数(有时以小写形式，有时以大写形式).我不知道如何解决这个问题?

In my project (ASP.net MVC) i have to return the name of a function (CSV File i read in) in lowercase. Because for now i have grouped the functions and it return functions with the same name (sometimes in lower case and sometimes in upper case). I don't know how to solve this problem?

//HomeController
public List<DescFunctionDataDTO> DescFunctionData()
{
    Console.WriteLine("DescFunctionData");

    var descItemsStamp = db.ChartDatas
        .GroupBy(x => new { x.Function });

    var descItems = descItemsStamp
        .Select(x => new DescFunctionDataDTO
        {
            function = x.Select(b => b.Function).Distinct(),
            functionavg = Math.Round(x.Average(y => y.Duration), 2),
        })
        .OrderByDescending(x => x.functionavg)
        .ToList();
    return descItems;
}

//DTO
public class DescFunctionDataDTO
{
    public IEnumerable<string> function { get; set; }
    public double functionavg { get; set; }
}

//JS-File
function showDescDuration() {

    $.getJSON(`/Home/DescFunctionData`)
        .then(data => {
            console.log(data);

            $('#rankingMax').find("tr:gt(0)").fadeOut().empty();
            var i = 1;
            for (let item of data) {
                console.log('loop');

                $('<tr>').appendTo('#rankingMax')
                    .append($('<td>').html("#"+i))
                    .append($('<td>').html(item.function))
                    .append($('<td>').html(item.functionavg + " ms"));
                i++;
            }
        });
}

推荐答案

您可以使用预定义的函数string.ToLower()这样，

you can use pre-defined function string.ToLower() like this,

var descItemsStamp = db.ChartDatas
    .GroupBy(x => new { x.Function });

var descItems = descItemsStamp
    .Select(x => new DescFunctionDataDTO
    {
        function = x.Select(b => b.Function.ToLower()).Distinct(),
        functionavg = Math.Round(x.Average(y => y.Duration), 2),
    })
    .OrderByDescending(x => x.functionavg)
    .ToList();
return descItems;

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