下载ASP.NET MVC C#字节数组列表中包含的多个文件 [英] Download multiple files contained in a list of byte array in ASP.NET MVC C#
问题描述
我正在开发ASP.NET MVC 5应用程序,并且编写了一个代码,该代码允许我以varbinary
的形式下载存储在SQL Server数据库中的文件,我可以通过以下方式下载单个文件:
I'm developing an ASP.NET MVC 5 application, and I wrote a code that allows me to download files stored in a SQL Server database as varbinary
, I'm able to download a single file with this:
public JsonResult PrepareSingleFile(int [] IdArray)
{
ImageContext _contexte = new ImageContext();
var response =_contexte.contents.Find(IdArray.FirstOrDefault());
//byte[] FileData =
Encoding.UTF8.GetBytes(response.image.ToString());
byte[] FileData = response.image;
Session["data"] = FileData;
Session["filename"] = response.FileName;
return Json(response.FileName);
}
public FileResult DownloadSingleFile()
{
var fname = Session["filename"];
var data = (byte[]) Session["data"];
//return File(data,"application/pdf");
return File(data,System.Net.Mime.MediaTypeNames.Application.Pdf, fname.ToString()+".pdf");
}
但是现在我想下载多个文件,因此我将每个文件的数据作为字节数组并将这些字节数组放入List<byte[]>
中,并且我想将这些文件下载为zip文件.我能做到吗?
But now I want to download multiple files, so I'm getting the data of each file as a byte array and putting those byte arrays inside a List<byte[]>
and I want to download those files as a zip file, so how can I do that?
我尝试过:
File(data,"the Mime Type", "file name.extension")
但是当data
是List<byte[]>
时不起作用.
推荐答案
You can do that using ZipArchive class available in .NET framework 4.5.
You may add a method in your controller that accepts a List<byte[]>
parameter and then converts each byte[] to a memory stream and puts it in a zip file like this one,
public FileResult DownloadMultipleFiles(List<byte[]> byteArrayList)
{
using (MemoryStream ms = new MemoryStream())
{
using (var archive = new ZipArchive(ms, ZipArchiveMode.Create, true))
{
foreach(var file in byteArrayList)
{
var entry = archive.CreateEntry(file.fileName +".pdf", CompressionLevel.Fastest);
using (var zipStream = entry.Open())
{
zipStream.Write(file, 0, file.Length);
}
}
}
return File(ms.ToArray(), "application/zip", "Archive.zip");
}
}
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