将多个参数从url传递到html.actionlink [英] Passing multiple parameters from url to html.actionlink

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本文介绍了将多个参数从url传递到html.actionlink的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

当我尝试通过URL传递多个参数时,我对MVC还是很陌生,并且在路由方面苦苦挣扎.

I'm fairly new to MVC and am struggling with routing when I try to pass multiple parameters via the URL.

从具有以下网址的页面:/PersonCAFDetail/Index/3?memberid=4

From a page with the URL: /PersonCAFDetail/Index/3?memberid=4

...我正在尝试将Html.ActionLink设置为指向Create动作,以使id = 3和memberid = 4.

...I'm trying to get an Html.ActionLink set to point to the Create action such that the id=3 and the memberid=4.

阅读过许多类似的帖子,看来以下应该可行:

Having read a number of similar posts it seems that the following should work:

@Html.ActionLink("Create New", "Create", null, new { memberid = "memberid" })

但是,这将导致如下创建URL:

However, this results in a URL being created as follows:

<a href="/PersonCAFDetail/Create/3" memberid="memberid">Create New</a>

我的路线设置为:

    routes.MapRoute(
        name: "PersonCAFDetail",
        url: "PersonCAFDetail/Create/{id}/{memberid}",
        defaults: new { controller = "PersonCAFDetail", action = "Create", id = "@\d+", memberid = @"\d+" }                        
        );

控制器接受以下两个参数:

The controller accepts two parameters as follows:

 public ActionResult Create(int id, int memberid)
        {
            int cafID = id;
            int personID = memberid;
            ViewBag.detailTypeID = new SelectList(db.tCAFDetailTypes, "detailTypeID", "detailType");
            ViewBag.cafID = new SelectList(db.tFamilyCAFs, "cafID", "issues");
            ViewBag.personID = new SelectList(db.tPersons, "personID", "forename");
            return View();
        }

任何帮助表示赞赏.

-------编辑模型------------

-------edit for model----------

namespace WhatWorks.Models
{
    using System;
    using System.Collections.Generic;
    using System.Linq;
    using System.Web;
    using System.Web.Mvc;
    using System.ComponentModel.DataAnnotations;

    public partial class tPersonCAFDetail
    {
        [Key, HiddenInput(DisplayValue=false)]
        public int cafID { get; set; }

        [Key, HiddenInput(DisplayValue = false)]
        public int personID { get; set; }

        [Key, HiddenInput(DisplayValue = false)]
        public int detailTypeID { get; set; }

        [Required, DataType(DataType.MultilineText)]
        public string notes { get; set; }


        public string FullName
        {
            get
            {
                return tPerson.forename + " " + tPerson.surname;
            }
        }

        public virtual tCAFDetailType tCAFDetailType { get; set; }
        public virtual tFamilyCAF tFamilyCAF { get; set; }
        public virtual tPerson tPerson { get; set; }
    }
}

推荐答案

最后,您需要向视图传递两个参数:

Finally, you need pass two parameters to the view:

索引操作:

public ActionResult Index(int id, int memberid)
{
    ...
    ViewBag.cafID = id;
    ViewBag.personID = memberid;
    return View();
}

Index.cshtml

Index.cshtml

@Html.ActionLink("Create New", "Create", "PersonCAFDetail", new { id=ViewBag.cafID , memberid =ViewBag.personID}, null)

然后检查您的路线语法... id = @"\ d +"

And Check your route syntax... id = @"\d+"

 routes.MapRoute(
    name: "PersonCAFDetail",
    url: "PersonCAFDetail/Create/{id}/{memberid}",
    defaults: new { controller = "PersonCAFDetail", action = "Create", id = @"\d+", memberid = @"\d+" }                        
    );

这篇关于将多个参数从url传递到html.actionlink的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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